You cannot. There are seven numbers and you cannot pair an odd number of values.
it would be a common sum of 91+8 2+7 3+6 4+5
4, 226, 208, 1810, 1612, 14The sum of each pair is 26 and both the numbers in a given pair are composite numbers.=======================The answer to the question is: 5
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
They are: 7 and 8
They are 9 and 6
9
it would be a common sum of 91+8 2+7 3+6 4+5
They have the same parity (odd or even).
You cannot. The sum and difference cannot be the same for any pair of non-zero numbers.
4, 226, 208, 1810, 1612, 14The sum of each pair is 26 and both the numbers in a given pair are composite numbers.=======================The answer to the question is: 5
There is no pair of consecutive even integers whose sum is 264 - as their average is divisible by 4, that must mean that the sum of the unit digits of each of the pair of numbers could never be a multiple of 4 - which 264 is.
The sum of any pair of prime numbers greater than 2 is an even number.
Any two odd numbers will have an odd product and an even sum.
2+3,11+3,3+17
An amicable number is one of a pair of numbers which have the property that the sum of the divisors of each, excluding itself, is equal to the other number.
Any pair of one even and one odd number will have an even product and an odd sum.
They are: 7 and 8