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Q: What percent of a sample of As-81 remains un-decayed after 43.3 seconds?
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What fraction of a sample of N 16 remains undecayed after 43.2 seconds?

1.5% remains after 43.2 seconds.


What is the fraction of a sample of tritium that remains undecayed after fifty years?

This fraction is 12,5 %.


What fraction of an original 20.00gram sample of nitrogen-16 remains unchanged after 36.0 seconds?

2


How many undecayed M and Ms would remain out of a sample of 600 M and Ms after three half lives?

75


Which fraction of an original 20.00-gram sample of nitrogen-16 remains unchanged after 36.0 seconds?

1/32


After one half-life what percent of the original uranium remains?

By definition, 50%. Half life is the time for half of the original sample to decay.


What fraction of a sample remains after three half lives?

An eighth remains.


What is the significance of a half life of a radioisotope?

It tells what fraction of a radioactive sample remains after a certain length of time.


Why After three half-lives what fraction of a radioactive sample remains?

The fraction that remains is 1/8.


If Astatine-218 has a half-life of 1.6 s Suppose you have a 1.2-g sample of astatine-218 How much of the sample remains unchanged after 6.4 seconds Explain how you solved the problem?

After 1.6 seconds, 0.6 g astatine-218 remains unchanged. This amount is reduced by half to 0.3 g at 3.2 seconds. It is halved again at 4.8 seconds to 0.15 g, and halved once more to 0.075 g unchanged after a total of 6.4 seconds.


After three half-lives what fraction of a radioactive sample remains?

1/8 of the original amount remains.


What happens to the mass of a radioactive isotope as it decays?

In reality, as the atoms gets decayed it gives out radiations such as alpha, beta and Gama. Alpha is a helium nucleus which is massive and beta is electron but fast moving and Gama is an electromagnetic radiation. So as the atom decays then its mass is likely to be reduced. Rutherford's radioactive law deals with the number of atoms undecayed present at an instant 't' given in the form N = No e-lambda t Here No is the total atoms present both decayed and undecayed in a sample. N is the number undecayed present lambda - the decay constant t - the time elapsed