75
8
You find the sample space by enumerating all of the possible outcomes. The sample space for three coins is [TTT, TTH, THT, THH, HTT, HTH, HHT, HHH].
The sample space when tossing a coin three times is [HHH, HHT, HTH, HTT, THH, THT, TTH, TTT]It does not matter if you toss one coin three times or three coins one time. The outcome is the same.
125
1/8 of the original amount remains.
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
It is 1/8 .
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
If I take a radioactive sample of 400 moles of an unknown substance and let it decay to the point of three half-lives I would have 50 moles left of the sample. 1/2 of what is left will decay in the next half-life. At the end of that half-life I will have 25 moles left of the unknown substance or 4/25.
Approx 1/8 will remain.
Not sure what you mean by "had-lives". After 3 half lives, approx 1/8 would remain.
There are three models of a fraction namely area model, liner model and set model.
Three half lives have elapsed. This can be determined by calculating how many times the original sample size must be halved to get to one eighth: (1/2) * (1/2) * (1/2) = 1/8.
It will take two half-lives or about 60.34 years for three-fourths of a Cs-137 sample to decay.
91.16% of the daughter product has formed after 3.5 half lives.
Three half-lives have elapsed. This is because each half-life reduces the amount to half of its original value. So, after one half-life, the amount is reduced to 50%, then to 25% after two half-lives, and 12.5% after three half-lives, which is closest to 3.125%.