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The answer depends on 3240 WHAT: seconds, days, years?
because
try using my formula.... ar=a(1/2)^2t therefore, 57(.05) = 57(1/2)^2t and 57s cancels out, .05 = 1/2^2t log .05 = log .5^2t divide log .5 from both sides, 4.32 = 2t t = 2.16, therefore 126 seconds or 2 minutes and 6 seconds
parameter !
Select the sample so that it will have the same percentages of people that are men and women as are in the system, and also match the percentage based on educational background and ethnicity
1.5% remains after 43.2 seconds.
After 50 years, approximately 50% of tritium will remain undecayed in a sample. Tritium has a half-life of about 12.3 years, which means that the amount of undecayed tritium decreases by half every 12.3 years.
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75
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
An eighth remains.
After one half-life, 50% (or half) of the original uranium remains.
It tells what fraction of a radioactive sample remains after a certain length of time.
The mass of a radioactive isotope remains constant as it decays. However, the atomic nucleus can change due to the emissions of particles or energy, which can result in the isotope transforming into a different element.
1/8 of the original amount remains.
The half-life remains constant for a particular radioactive substance, regardless of how old the sample is. This means that the rate at which the substance decays and the time it takes for half of it to decay remains consistent over time.
One eighth remains.