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Mean = 100

Standard Deviation = 25

(120 -100) / 25 = 0.80

th z value of .80 from the table = .2881

P(100-120) = 28.81%

What percentage of calls are completed in less than 60 minutes ?

(60 - 100) / 25 = - 1.6

from the table the z value is .4452

(one side), then : .5000 - .4452 = .0548

P(60) = 5.48%

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Q: What percentage of calls are completed between 100 and 120 minutes with a mean time of 100 minutes for office calls with a standard deviation of 25 minutes?
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