Q: What points on a graph would represent y 4x?

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Find the two X intercepts. Set = to 0 4X + 3 = 0 X = -3/4 ( while Y = 3) 4X - 2 = 0 X = 1/2 ( while Y = -2) Now you have two points for each parallel line and can draw the graph

6 - 4x = 13 So 4x = -7 or x = -7/4 = -1.75 In 1-dimension, the graph would consist of the single point x = -1.75 In 2-dimensions, the graph would consist of the vertical line, passing through x = -1.75 In 3-dimensions, the graph would consist of the plane parallel to the y-z axes and passing through x = -1.75

The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.

Select a set of values for x. For each value of x calculate the corresponding value of y using the function x2 - 4x - 4. Plot these points and join together with as smooth a curve as you can manage.

y = -4x The y-intercept is zero. That is, the graph passes through the origin.

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If you mean y = -4x-6 then it is a straight line equation that can be graphed on the Cartesian plane

Since there are no "following" points, none of them.

It is a straight line which goes through the points (2,0) and (0, -4)

Find the two X intercepts. Set = to 0 4X + 3 = 0 X = -3/4 ( while Y = 3) 4X - 2 = 0 X = 1/2 ( while Y = -2) Now you have two points for each parallel line and can draw the graph

6 - 4x = 13 So 4x = -7 or x = -7/4 = -1.75 In 1-dimension, the graph would consist of the single point x = -1.75 In 2-dimensions, the graph would consist of the vertical line, passing through x = -1.75 In 3-dimensions, the graph would consist of the plane parallel to the y-z axes and passing through x = -1.75

One way would be to graph the two equations: the parabola y = xÂ² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)

The y-intercept of the graph of 4x + 2y =12 is probably 6

Select a few values for "x"; calculate the corresponding "y" values; plot the points on the graphing paper; join the points with lines. In fact, that's the method used to draw just about any graph.

The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.

The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.

Select a set of values for x. For each value of x calculate the corresponding value of y using the function x2 - 4x - 4. Plot these points and join together with as smooth a curve as you can manage.

y = -4x The y-intercept is zero. That is, the graph passes through the origin.