y=xsquared-4x+2
Since there are no "following" points, none of them.
One way would be to graph the two equations: the parabola y = x² + 4x + 3, and the straight line y = 2x + 6. The two points where the straight line intersects the parabola are the solutions. The 2 solution points are (1,8) and (-3,0)
y = 2x-5 4x-y = 7 => y = 4x-7 2x-5 = 4x-7 2x-4x = 5-7 -2x = -2 x = 1 Therefore by substituting: x = 1 and y = -3
it will form a parabola on the graph with the vertex at point (0,0) and points at (1,1), (-1,1), (2,4), (-2,4)......
y=xsquared-4x+2
y = -4x The y-intercept is zero. That is, the graph passes through the origin.
The graph is a circle with a radius of 6, centered at the origin.
Y = x2 + 4x + 11OK. That's very interesting.Is there a question ?
4x-24y = 24 -24y = -4x+24 y = 1/6x-1 So the y intercept is -1
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
Same way you graph y = -4x - 0.5
4x+2y = 12 2y = -4x+12 y = -2x+6 So the y intercept is 6 and the slope is -2
Solve for Y algebraically. 4X + 8Y = 16 8Y = - 4X + 16 Y = - 1/2X + 2 graph and see that the Y intercept = 2
Need signs between terms.
Since there are no "following" points, none of them.
-4x=7y-28 -4x+28=7y -4x/7+4=y A line with a y-int of 4 and a slope of -4/7