(4,5) and (2,0)
Discuss how you can use the zeros of the numerator and the zeros of the denominator of a rational function to determine whether the graph lies below or above the x-axis in a specified interval?
hx = -2x2We have to assume that 'h' is some constant that you know but we don't.The graph of this equation contains no ordered pairs, since there's only one variable.If you must graph it, then the space you need to use is the number line. The twosolutions to the equation are points on the number line ... one point at [ zero ],and the other at [ - h/2 ] .
that's true
There are infinitely many points on the line. One such is (-6, 3.33...)
(4,1)
(4,5) and (2,0)
In two dimensions, the infinitely many points with coordinates of the form (x, x-2) where x is any number.
Eight.
Discuss how you can use the zeros of the numerator and the zeros of the denominator of a rational function to determine whether the graph lies below or above the x-axis in a specified interval?
hx = -2x2We have to assume that 'h' is some constant that you know but we don't.The graph of this equation contains no ordered pairs, since there's only one variable.If you must graph it, then the space you need to use is the number line. The twosolutions to the equation are points on the number line ... one point at [ zero ],and the other at [ - h/2 ] .
Done see any following points. Ill give you a few that come from the equation. x=1 and y=5 x=2 and y=6 x=3 and y=9 x=11 and y=105
The points are (-0.25, 0) and (0, 1)
that's true
Exactly halfway
y = x2 + 4 The graph is a parabola, with its nose at y=4 on the y-axis, and opening upward.
Precisely midway. That is to say, at their mean (average).