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What polygon has 6 diagonals?

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Anonymous

15y ago
Updated: 10/17/2024

There cannot be a polygon with 6 diagonals.

A polygon with n vertices has n*(n-3)/2 diagonals.

If this is 6, then n*(n-3)/2 = 6

therefore n*(n-3) = 12

and so n^2 - 3n - 12 = 0

The only solutions to this equation are n = 1.5-sqrt(57)/2 or 1.5+sqrt(57)/2.

However, n, being the NUMBER of vertices cannot be an irrational number and so there is no solution.

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Wiki User

10y ago

What else can I help you with?