In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
There are three diagonal lines in a six sided Polygon(Hexagon)
it has 3 sides not 6
3to 8 sides
The polygon that has 6 sides is called a hexagon
A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.
6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.
It is: 8-2 = 6 triangles
It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.
1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2
A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.
There are three diagonal lines in a six sided Polygon(Hexagon)
The formula for the number of diagonals that an N-sided polygon has is# diagonals = N(N-3)/2N(N-3)/29(N-3)/29*(9-3)/29*6/2 = 54/227
The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.
A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon
No not normally. The formula of the number of diagonals is (n/2)(n - 3). (n/2)(n - 3) = 10 n(n - 3) = 20 n2 - 3n - 20 = 0 we cannot factor it as (n - r1)(n - r2), where r1 and r2 are natural numbers, so there is any polygon with 10 diagonals.