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Q: How many diagonals does a polygon with 6 sides have?
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How many diagonals are in a nine sided figure?

A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.


How many diagonals are there in a hexagon?

In a polygon with n sides there are n*(n-3)/2 diagonals. For a hexagon, n = 6 giving 9 diagonals in all.


How many diagonals a heptagon has?

6 * * * * * No! The number of diagonals in a polygon with n sides is 1/2*n*(n - 3). So when n = 7 this gives the number of diagonals in a heptagon is 14.


How many triangles will be formed if you draw diagonals from a single vertex of a convex polygon with 8 sides?

It is: 8-2 = 6 triangles


How many diagonals in a 9 sided polygon?

It depends. It doesn't have to always be the same shape. So it can be 0, it can be 1, as long as it has straight lines and is a closed figure, it's a polygon. * * * * * What? A polygon with n sides has n*(n-3)/2 diagonals. Simple as that. So a 9 sided polygon has 9*6/2 = 27 diagonals.


How many diagonals does a decagon have?

1oo diagonals, because 1 side has 10 diagonals so 10 sides (10x10) = 100 diagonals! This is the correct answer..... a decagon has 35 diagonals. The equation for the this is D=n(n-3)/2 meaning diagonals = number of sides (N) multiplied by number of sides minus 3. and that number over 2. D=10(10-3)/2


How many diagonals are in a 7 sided polygon?

A 4-sided polygon has 2 diagonals. A 5-sided polygon, 5. 6-sided, 9. By induction, an n-sided polygon has 'n*(n-3)/2' diagonals. "n" is how many sides a shape has. so, (7)*(7-3)/2 now we have, 7*4/2 so, 28/2 = 14 Therefore, a 7-sided polygon would have 14 diagonals.


How many diagonals in a 6 sided polygon?

There are three diagonal lines in a six sided Polygon(Hexagon)


How many parallel sides in 9-sided polygon?

The formula for the number of diagonals that an N-sided polygon has is# diagonals = N(N-3)/2N(N-3)/29(N-3)/29*(9-3)/29*6/2 = 54/227


How many diagonals do hexagons have?

The number of diagonals in an n-sided polygon is given by nC2 - n (where n is the number of sides of the polygon) or in the expanded form: factorial (n) _______________________ {factorial (2) * factorial (n-2)} substituting (n = 6) for a hexagon we get the number of diagonals as 9. Similarly, substituting (n=5) for a pentagon we get the number of diagonals as 5.


Which polygon has 6 sides and 8 sides?

A polygon with 6 sides is a hexagon and a polygon with 8 sides is an octagon


Can a polygon have exactly 10 diagonals?

No not normally. The formula of the number of diagonals is (n/2)(n - 3). (n/2)(n - 3) = 10 n(n - 3) = 20 n2 - 3n - 20 = 0 we cannot factor it as (n - r1)(n - r2), where r1 and r2 are natural numbers, so there is any polygon with 10 diagonals.