103 and 5
f(n) = n^3 + 4n + 2 = prime This works for at least two numbers f(0) = 2 f(1) = 7
#include#includeint a,f,n,sum=0; printf("Enter any number"); scanf("%d",&n); f=1; for(a=1;a<=n;a ); { f=f*a; } for(f=1;f<=n;f ); { sum=sum f; } printf("sumation of factorial numbers :",sum); getch(); }
False
Just 2.
Fibonacci primes are Fibonacci numbers that are also prime numbers. The Fibonacci sequence, defined as F(0) = 0, F(1) = 1, and F(n) = F(n-1) + F(n-2) for n ≥ 2, produces a series of numbers. Among these, the Fibonacci primes include numbers like 2, 3, 5, 13, and 89, which are prime and appear within the Fibonacci sequence. Not all Fibonacci numbers are prime, making Fibonacci primes a specific subset of both prime numbers and Fibonacci numbers.
6
The GCF of any set of distinct prime numbers is 1.
Mean = sum of all numbers divided by number of numbers you summed. Call numbers a, b, c, d, e, f (a+b+c+d+e+f)/6 = mean
108°f=136.8°c
Expressed as a sum in hexadecimal form, F + D = 1C.
/*mycfiles.wordpress.com To Calculate Sum & Average of 4 no.*/ #include<stdio.h> #include<conio.h> void main() { float a,b,c,d,sum,avg; clrscr(); printf("Enter the 4 nos.\n\n"); scanf("%f%f%f%f",&a,&b,&c,&d); sum=a+b+c+d; avg=(a+b+c+d)/4; printf("\nSum is= %f\nAverage is= %f",sum,avg); getch(); }
Any number of the form n = a*b*c*d*e*f where a, b, c, d, e and f are different prime numbers. n has 26 = 64 factors in total, of which 1 is the number 1 (neither prime nor composite), 6 are prime, and the remaining 57 are composite.