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Itself and any of its multiples

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Algebra

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A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

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Q: What r all the numbers divisible by 3?
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How many positive three digit integers are divisible by neither 2 nor 3?

There are 300 three digit numbers that are divisible by neither 2 nor 3. There are 999 - 100 + 1 = 900 three digit numbers. 100 ÷ 2 = 50 → first three digit number divisible by 2 is 50 × 2 =100 999 ÷ 2 = 499 r 1 → last three digit number divisible by 2 is 499 × 2 = 998 → there are 499 - 50 + 1 = 450 three digit numbers divisible by 2. 100 ÷ 3 = 33 r 1 → first three digit number divisible by 3 is 34 × 3 = 102 999 ÷ 3 = 333 → last three digit number divisible by 3 is 333 × 3 = 999 → there are 333 - 34 + 1 = 300 three digit numbers divisible by 3. The lowest common multiple of 2 and 3 is 6, so these have been counted in both those divisible by 2 and those divisible by 3. 100 ÷ 6 = 16 r 4 → first three digit number divisible by 6 is 17 × 6 = 102 999 ÷ 6 = 166 r 3 → last three digit number divisible by 6 is 166 × 6 = 996 → there are 166 - 17 + 1 = 150 → there are 450 + 300 - 150 = 600 three digit numbers that are divisible by either 2 or 3 (or both). → there are 900 - 600 = 300 three digit numbers that are divisible by neither 2 nor 3.


What numbers are not divisible by 29?

Every number is divisible by any non-zero number.Any element of the set of numbers of the form 29*k + r, where k is an integer and 0<r<29, is not evenly divisible.


How many numbers between 100 to 500 are divisible by 6?

There are 67 numbers between 100 and 500 divisible by 6. The first number greater than 100 divisible by 6: 100 ÷ 6 = 16 r 4 → first number divisible by 6 is 6 × 17 = 102 Last number less than 500 divisible by 6: 500 ÷ 6 = 83 r 2 → last number divisible by 6 is 6 × 83 = 498 → all multiples of 6 between 17 × 6 and 83 × 6 inclusive are the numbers between 100 and 500 that are divisible by 6. → there are 83 - 17 + 1 = 67 such numbers.


How many three digits natural numbers are divisible by 4?

The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.


How many natural numbers between 150 and 300 are divisible by 9?

150 ÷ 9 = 16 r 6 → the first natural number between 150 and 300 divisible by 9 is 9 × 17 (=154)300 ÷ 9 = 33 r 3 → the last natural number between 150 and 300 divisible by 9 is 9 × 33 (=297)→ there are 33 - 17 + 1 = 17 natural numbers between 150 and 300 divisible by 9.


What are the numbers the letters r on?

all numbers with three and four in it


What is the set of all real numbers?

The set of all real numbers (R) is the set of all rational and irrational numbers. The set R has no restrictions in its domain and so includes (-∞, ∞).


Which one is NOT divisible by 9 234 345 or 567?

345 is not divisible by 9. A quick rule for checking to see if a number is divisible by 9 is to add all of the number's digits. If their sum is divisible by 9, so is the number.2+3+4 = 9, which is divisible by 9, so 234 is divisible by 9. (234/9 = 16)3+4+5 = 123, which is not divisible by 9, so 345 is not divisible by 9 (345/9 = 38 r 3)5+6+7 = 18, which is divisible by 9, so 567 is divisible by 9 (567/9 = 63)


What r the 3 numbers that have 2 4 and 8 as factors?

Calculate the least common multiple of the three numbers. Any multiple of that has all those numbers as factors.


What is are all the integers?

All integers are the elements of the set of integers, I, which is one of the components of the set of all real numbers, R. I = {..., - 3, -2, -1, 0, 1, 2, 3, ...}.


What are the prime numbers r in 42?

They are: 2, 3 and 7


How do you find the median of numbers?

Put the numbers in order. Add them all together then divide by the amount of numbers in the line. For example: 1 2 3 4 5 6 = 21 21 divide by 6 is 3 r 3 so your answer is 3.3


Which number is divisible by 5 and 9?

When you are trying to find a common number that is divisible by two different numbers, you multiply the two together. So, for this example, you multiply 9 and 5, which equals 45. Therefore, 45 would be divisible by both 9 and 5.


How do the numbers in the โ€œR 3โ€ and โ€œT 2โ€ columns compare?

r3


What numbers r rational?

All those numbers than can b represented as one integer over another integer r rational.


What is the 118th sequence in y-r-r-y-r-r-y-r-r-y-r-r-y-r-r?

It is y. Every third letter is r, immediately followed by y, and since 117 is divisible by 3, it is r. Therefore, 118 is y.


How do you figure out how to write a fraction using numbers For example the math problem is two divided by three?

all you do as a fration it is 2/3 then all you do is divide 3 into 2 which will be 1 r.1


How many number between 0 and 100 are divisible by 0?

only 1. 0 is divisible by 0 but nothing but 0 is ever because no number multiplied by 0 can be anything other than 0. so only 0 can be divided by 0. with variables Y= all real numbers. R= all numbers other than 0 0xY=0 soo 0/0=0 but because the product is always zero Rx0=0 R/0=undefined so your answer is only 1 number.


Can rational numbers r?

No, rational numbers cannot r.


What r two numbers that have 2 3 5 as factors?

30 and 60


Find the smallest number in a GP whose sum is 38 and product 1728?

Let the three numbers in GP: a/r, a, ar---------(A)Where '^' is power of . . .Sum of these numbers are:a/r +a +ar = 38a(1\r+1+r) = 38 ---- (1)Product of these numbers are:a^3 = 1728= (12)^3a = 12Putting the value of a in (1) you will get:12(1\r+1+r) = 38And factorising, we getr = 2/3 or r = 3/2Sub. the r and a value in (A), we get8,12,18 or 18,12,8. When a = 12And smallest no. is 8.


What are less then 52 and have 4 divisible by it?

If r is an integer then r = 1, 2 or 4.


Is 500 one of the multiples of 3?

No. To be divisible by 3, if the sum of the digits is divisible by 3 so is the original number, otherwise the remainder when the sum is divided by 3 is the remainder when the original number is divided by 3. 5 + 0 + 0 = 5 5 ÷ 3 = 1 r 2, so 500 ÷ 3 has remainder 2.


How does each multiplication problem compare to its cooresponding division problem?

By inverting the numbers. For example, if:2 x 3 = 6 then: 6 / 3 = 2


What are the numbers between 200 250 that are divisible by 3 but not 2?

200 ÷ 3 = 66 r 2 → first multiple of 3 greater than or equal to 200 is 67 (x 3 = 201) 250 ÷ 3 = 83 r 3 → last multiple of 3 less than or equal to 250 is 83 (x 3 = 249) All multiples of 2 are even, so want all multiples of 3 that are not even, namely the odd multiples of 3; so want 67 x 3, 69 x 3, 71 x 3, ... 83 x 3 which are: 201, 207, 213, 219, 225, 231, 237, 243, 249.