There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.
9
8C3 = 56 of them
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.
45*44*43*42/(4*3*2*1) = 148995
(43*42*41*40*39)/(5*4*3*2*1) = 962598
There are 5245786 possible combinations and I am not stupid enough to try and list what they are!
9
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
8C3 = 56 of them
45*44*43*42*41/(5*4*3*2*1) = 1,221,759
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.
I dont understand what you are asking.