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To find the number of combinations of 3 numbers from a set of 42 numbers, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 42 ) and ( r = 3 ). So, ( C(42, 3) = \frac{42!}{3!(42-3)!} = \frac{42 \times 41 \times 40}{3 \times 2 \times 1} = 11480 ). Therefore, there are 11,480 combinations of 3 numbers from 42 numbers.

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Q: How many combinations of 3 numbers are there in 42 numbers?
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