To find the number of combinations of 3 numbers from a set of 42 numbers, you can use the combination formula ( C(n, r) = \frac{n!}{r!(n-r)!} ). Here, ( n = 42 ) and ( r = 3 ). So, ( C(42, 3) = \frac{42!}{3!(42-3)!} = \frac{42 \times 41 \times 40}{3 \times 2 \times 1} = 11480 ). Therefore, there are 11,480 combinations of 3 numbers from 42 numbers.
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There are (42*41*40*39*38*37)/(6*5*4*3*2*1) = 5 245 786 combinations.
9
8C3 = 56 of them
There are 23C3 = 23!/(20!*3!) = 23*22*21/(3*2*1) = 1,771 combinations.
If the numbers can be repeated and the numbers are 0-9 then there are 1000 different combinations.