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2+2=4
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What is 1 plus 2 plus 4 plus 8 plus .?
let 1+2+4+8+...... =s s= 1+2(1+2+4+8+........) s=1+2s s=-1 but sum of infinite terms cannot be -1 so, what's the answer
What is the answer 2 2 plus 2 plus 4?
12 blackdrago98's answer: If the question is: "What is the answer to '2 plus 2 plus 4'?" then it is 8. If the question is: "What is the answer: 2(2+2+4)?"
How do you get -2 equals 4r plus s solving for s?
s = -2 -4r
What is the answer to -2 equals 4r plus s solving for s?
-2=4r+s s=-4r-2 or s=-(4r+2)
What is the answers from 32 plus 15 plus 25 plus 8 plus s equals 10 to the 2 power?
s = 20
Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Cd^2+(aq) + 2Cl^-(aq) +2Na^+(aq) + S^2-(sq) ==> CdS(s) + 2Na^+(aq) + 2Cl^-(aq)The 2Na^+(aq) and the 2 Cl^-(aq) are spectator ions as they appear on both sides of the equation. Thus, the NET reaction is ...Cd^2+(aq) + S^2-(aq) ==> CdS(s)What else was your question. This is classed as a double replacement reaction.
How to Balance the following equation HCl plus Na2S------H2S plus NaCl?
2HCl + Na(2)S-----> H(2)S + 2NaCl
What does 4s2 plus s-14 factor out to?
4s^2 + s - 14 = (4s - 7)(s + 2)
Given the complete ionic equation Cd2 plus (aq) plus 2Cl-(aq) plus 2Na plus (aq) plus S2-(aq) CdS(s) plus 2Na plus (aq) plus 2Cl-(aq)?
Net Ionic: Cd^+2+(aq) + S^2-(aq) ==> CdS(s)The Na^+ and Cl^- are spectator ions.
What is the new oxidation number for cr2o7-2 plus 8h plus 3so3-2 2cr3 plus 3sov-2 plus 4h20?
oxidation number of S is +6.It oxidize into SO4 ^-2
What are the solution sets 4s2 plus 12s plus 9 equals 0?
The solutions are: s = -3/2 and s = -3/2 they have equal roots
What s 1 plus 1?
2 or window
