let 1+2+4+8+...... =s s= 1+2(1+2+4+8+........) s=1+2s s=-1 but sum of infinite terms cannot be -1 so, what's the answer
14
1
Another Answer: 12*0+1 = 1
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
it equal 18 (eight- teen)
S = {-5, 1}
It equals 28. ,
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 - 1 + 1 + 1 + 1 + 1 + 1 x 0= (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) + (1 - 1) + (1 + 1 + 1 + 1) + (1 x 0)= 9 + 0 + 4 + 0= 13It depends on if the entire equation is being multiplied by 0 or just the last plus 1. If it is just the last plus 1 then the answer is 13 like shown above. If the entire problem is being multiplied by 0 then the answer is 0.
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It equals 7
1,001,001,001,100
1/2
32
Without any further information, the expression, "s plus 6" has no answer.
1/2 plus 1/2 plus 1/4 plus 3/4 is two.
Neither. It is 50 minus 10 plus 5 plus 1 plus1plus1.