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∙ 12y agolet 1+2+4+8+...... =s s= 1+2(1+2+4+8+........) s=1+2s s=-1 but sum of infinite terms cannot be -1 so, what's the answer
14
1
Another Answer: 12*0+1 = 1
1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 11 - 9,999,999 = - 9,999,978
let 1+2+4+8+...... =s s= 1+2(1+2+4+8+........) s=1+2s s=-1 but sum of infinite terms cannot be -1 so, what's the answer
1S+1S+1 = 3 Note that 1 raised to any power is always 1.
no it;s not the answer is 2
(xn+2-1)/(x2-1)
That depends on the value of s.
its 12(s-1/2)(s+1) is that what you were looking for?
-1
s=4
s = 2
14
It is 35.
7 is the answer. The order of operations would be to multiply the 2 times 1 and then add the five other 1's. (Unless there are parenthesis around some of the numbers) Here are the orders # Parentheses # Exponents # Multiplication and Division # Addition and Subtraction