All the rest of them.
s
3. Ignore the 8's in the sequence and you get 9, 6, 4, 3,_. 9-3=6 6-2=4 4-1=3 3-0=3
In this sequence s the nth term is s(n) calculated as follows where s(1) = 1: s(n) = (n - 1)(s(n - 1)) eg the 5th number (s(5)) = 4th number times 4 so next number s(7) will be 6 times s(6) ie 720
An element S_P_U could be SULPHUR (S)
When counting by 5's, the next number after 100 would be 105. This is because you are adding 5 to each subsequent number in the sequence. Therefore, after 100, the next number in the sequence would be 105.
s, the sequence is one two three four five six, so the next number is seven, so the answer is s
Well, honey, that sequence is all over the place like a drunk driver on a highway. But if we're going by the pattern of adding the number of digits in each number to the end, the next number would be 1113122115. But who knows, maybe the sequence will throw a curveball and give us something completely unexpected.
Every convergent sequence is Cauchy. Every Cauchy sequence in Rk is convergent, but this is not true in general, for example within S= {x:x€R, x>0} the Cauchy sequence (1/n) has no limit in s since 0 is not a member of S.
Using binary code. A sequence of "0's" and "1's".
212
The Roaring 20's - 1960 Among the Missing 1-27 was released on: USA: 6 May 1961
There are many sequences with this property: The sequence with every term equal to 0 has this property. In fact the sequence can be anything you like as long you make sure the 58th term is the sum of the first 10 terms. A more specific case: If you are dealing with an arithmetic sequence, i.e. a sequence of the form s(n)=a+bn for constants a and b, we can derive a relationship between a and b: s(1)+s(2)+...+s(10)=10a+55b and s(58)=a+58b From this, it follows that if s(1)+s(2)+...+s(10)=s(58), then we have 10a+55b=a+58b, which implies that 3a=b. Again, there are infinitely many sequences with this property, but if it is an arithmetic sequence, it will be of the general form s(n)=a+3an=a(3n+1)