All the rest of them.
3. Ignore the 8's in the sequence and you get 9, 6, 4, 3,_. 9-3=6 6-2=4 4-1=3 3-0=3
s
In this sequence s the nth term is s(n) calculated as follows where s(1) = 1: s(n) = (n - 1)(s(n - 1)) eg the 5th number (s(5)) = 4th number times 4 so next number s(7) will be 6 times s(6) ie 720
An element S_P_U could be SULPHUR (S)
When counting by 5's, the next number after 100 would be 105. This is because you are adding 5 to each subsequent number in the sequence. Therefore, after 100, the next number in the sequence would be 105.
1113122115 Each subsequent term of the sequence is the count of each digit in the previous term: 5 → one-"5" = 15 15 → one-"1"-one-"5" = 1115 1115 → three-"1"s-one-"5" = 3115 3115 → one-"3"-two-"1"s-one-"5" = 132115 the next term is: 132115 → one-"1"-one-"3"-one-"2"-two-"1"s-one-"5" = 1113122115
s, the sequence is one two three four five six, so the next number is seven, so the answer is s
Every convergent sequence is Cauchy. Every Cauchy sequence in Rk is convergent, but this is not true in general, for example within S= {x:x€R, x>0} the Cauchy sequence (1/n) has no limit in s since 0 is not a member of S.
Using binary code. A sequence of "0's" and "1's".
The Roaring 20's - 1960 Among the Missing 1-27 was released on: USA: 6 May 1961
212
Next in sequence is 13112221.This series describes each number that came before it:1 [One]11 [One One]21 [Two One(s)]1211 [One Two and One One(s)]111221 [One One, One Two, and Two One(s)]312211 [Three One(s), Two Two(s), and One One]The next number in the series is:13112221 [One Three, One One, Two Two(s), Two One(s)]