You would need at least 3 AWG at 120 volts, giving you a 4.8 percent voltage drop at the maximum load of 37.5 amps (using 30 Amps at the ordinary 80 percent rated capacity of the circuit). For 240 volts you would only need 6 AWG.
This is a voltage drop question. A voltage must be stated to answer this question.
See discuss question below.
A #10 copper wire with an insulation rated at 90 degree C has a rating of 30 amps. Over the distance of 12 feet, there is no appreciable voltage drop that will effect the load.
A #8 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 50 and 55 amps respectively. When distance comes into the equation, the question becomes a voltage drop question and a supply voltage over the 200 feet has to be stated.
Looks like You need to run #10 to get 10 amps at 600 feet. You will have a voltage drop. You might only have aprox. 107.676 volts at the end of the run. You will do a little better if you use strand wire. Good luck.
A #16 copper conductor is not a wiring size that is used in homes. This is because the smallest breaker for residential use is rated for 15 amps. A #16 copper conductor is only rated at 13 amps. For a load of 13 amps over 100 feet a #12 copper would be required.
I would recommend no smaller than #8awg copper. This is derived by 8awg copper ampacity of 40 amps multiplied by 80% load rating to get 32 amps. Then calculating for voltage drop over this distance shows a drop of 5.9 volts or 2.5% which is negligible so not accounted for. So like i said no smaller than #8awg copper.
A #4 copper conductor will limit the voltage drop to 3% or less when supplying 25 amps for 400 feet on a 120 volt system.
A #10 copper wire with an insulation rated at 90 degree C has a rating of 30 amps. Over the distance of 12 feet, there is no appreciable voltage drop that will effect the load.
A #8 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 50 and 55 amps respectively. When distance comes into the equation, the question becomes a voltage drop question and a supply voltage over the 200 feet has to be stated.
A circuit current of 8 amps over a 180 foot distance with a voltage supply of 120 volts will need to use a #10 copper conductor. This will limit the voltage drop to 3 percent.
Because it has to turn over a large engine. This takes plenty of cranking amps. To create that much amps takes a large battery with plenty of storage space for the current needed.
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Looks like You need to run #10 to get 10 amps at 600 feet. You will have a voltage drop. You might only have aprox. 107.676 volts at the end of the run. You will do a little better if you use strand wire. Good luck.
when you serve the ball it has to go at least 30 feet to go over the net, but it cant go over 60 feet. it has to be over 7 feet and 4 inches at the 30 foot mark.
You have to know the maximum amps you wish to deliver or draw of the device or devices you wish to power. There are charts on the internet for wire gauges and distance that you can follow. For example: A 12 gauge wire will handle 20 amps safely for runs up to 100 feet. You go down 1 gauge for runs over 100 feet. So if you are running 175 feet at 20 amps you should use 10 gauge so voltage drops don't occur. Voltage has no effect on rated current output other than selecting a wire or cable that is rated for the working voltages. 20 amps at 240 volts is the same as 20 amps at 120 volts. As long as the wire is rated at 240 volts, it will carry 20 amps at voltages less than 240 the same.
A #16 copper conductor is not a wiring size that is used in homes. This is because the smallest breaker for residential use is rated for 15 amps. A #16 copper conductor is only rated at 13 amps. For a load of 13 amps over 100 feet a #12 copper would be required.
Each baseboard heater will draw a little over 4 amps at 120 volts or 2 Amps at 240 volts. The total number of baseboards on a circuit will draw the sum of these amps. Keep the load under 80% of the amperage rating of the breaker.
by increasing distance over which the force is applied