The Canadian Electrical Code requires a 1000MCM copper wire with a insulation factor of 90 degree C is rated at 585 amps. Quite a coincidence.
The National Electrical Code requires a 900 kcmil copper conductor with an insulation rated for 90 degrees C for 585 amps..
There are two distinct questions here. To determine the wire size to carry 15000 volts the circuits load amperage must be stated. The wire size for a 550 amp service is, an 800 MCM copper conductor with an insulation factor of 90 degrees C. This conductor is rated at 555 amps. Parallel 250 MCM will give you a total capacity of 580 amps. A triple run of 2/0 will give you a total capacity of 585 amps.
Conductors by code are only allowed to be loaded up to 80 percent. In this case an over size wire set will be higher that what the wire is rated for in the code book. A 600 MCM copper conductor with an insulation factor of 90 degrees C is rated at 455 amps. Paralleled together will give an ampacity of 910 amps. After the derate the maximum amperage allowed is 728 amps. So to get the full 900 amp the wire size has to be increased to a 1000 MCM copper conductor with an insulation factor of 90 degrees C which is rated at 585 amps. Paralleled this give you an ampacity of 1170 amps. After the derate the maximum amperage allowed is 1170 x 80% = 936 amps
585
No: 585 divided by 6 is 97 with remainder 3.
Yes, 585 divided by 9 is 65
585: Quinientos ochenta y cinco
585 + 367 = 952
9
585 multiplied by 13 is 7,605.
585 is most likely the stamp of the gold in the Jewelry. 585 stands for 14kt gold.
Add the digits in 585 i.e. 5+8+5=18 18 is divisible by 3 Therefore, 585 is divisible by 3
As a product of its prime factors: 3*3*5*13 = 585 or as 32*5*13 = 585