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Conductors by code are only allowed to be loaded up to 80 percent. In this case an over size wire set will be higher that what the wire is rated for in the code book. A 600 MCM copper conductor with an insulation factor of 90 degrees C is rated at 455 amps. Paralleled together will give an ampacity of 910 amps. After the derate the maximum amperage allowed is 728 amps. So to get the full 900 amp the wire size has to be increased to a 1000 MCM copper conductor with an insulation factor of 90 degrees C which is rated at 585 amps. Paralleled this give you an ampacity of 1170 amps. After the derate the maximum amperage allowed is 1170 x 80% = 936 amps
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Can you wire a 40 amp range to a 100 amp box if you are already about at 60 amps?
Yes, you can, you just can't have 100 amps running through the box at one time. For instance, I have a 450 amp box in my house, but all the breakers add up to 900.
What is the ampacity of an ACSR?
WIRE AMPACITY TABLE ACSR DIA.(OUt) CCC 795MCM 1.093" 900 A 556.5MCM 0.927" 730 A 336.4MCM 0.721" 530 A 4/0 0.563" 340 A 3/0 0.502" 300 A 2/0 0.447" 270 A 1/0 0.398" 230 A 2 0.316" 180 A 4 0.250" 140 A 6 0.198" 100 A
What would be the resonant frequency for a series RLC circuit with the following components a 1 kilo ohm resistor a 900 micro hertz inductor and a 0.014 microfarad capacitor?
The resonant frequency is set by the L and the C: 900 microhenrys and 0.014 microfarad would resonate at a frequency given by: F = 1/ [2 pi sqrt(LC)] If the components are in 'micros' the answer is in Megahertz. In this case the resonant frequency in MHz is: F = 1/ [2 pi sqrt(900 x 0.014)] or 0.0448 MHz, 44.8 kHz. The reactance of the inductor and the capacitor is 253 ohms, so adding a 1000 ohm resistor in parallel would give a tuned circuit with a Q of 1000 / 253 or 3.9.
What will be the torque of motor 7.5HP and RPM 900?
43.7667 ft•lb
What is minimum size resistor in watts to use with a 9 volt 900 ohm resistor?
Take your pick:P = V x I (Power = Voltage x Current)or:P = V2 / R (Power = Voltage2 / Resistance)or:P = I2 *R (Power = Current2 x Resistance)(the last two equations come from combining the ohms law equation R=V/I with the power equation P=VxI)In the question above you have resistance and voltage therefore:P = V2 / R = 92 / 900 = 0.090W = 90mW(i believe 0.125W is the smallest resistor you can get)hope that helps
