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Using the physics formula:

v2 = u2 + 2as

v - final velocity

u - initial velocity

a - acceleration

s - distance

When the object leaves the ground it is being slowed down by gravity until it stops so the acceleration equals -9.8m/s2 and as it will stop at 2.5 meters v = 0. U is the value we want to find out:

02 = u2 + (2 *-9.8*2.5)

49 = u2

So the object must leave the ground at 7m/s.

By the way this is ignoring air resistance.

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Q: What speed must an object leave the ground to travel 2.5 meters up?
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