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Using the physics formula:
v2 = u2 + 2as
v - final velocity
u - initial velocity
a - acceleration
s - distance
When the object leaves the ground it is being slowed down by gravity until it stops so the acceleration equals -9.8m/s2 and as it will stop at 2.5 meters v = 0. U is the value we want to find out:
02 = u2 + (2 *-9.8*2.5)
49 = u2
So the object must leave the ground at 7m/s.
By the way this is ignoring air resistance.
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