If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
Thy are 8, 10 and 12.
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
The sum of two odd numbers is even and the sum of an even number and an odd number is odd.So the sum of three consecutive odd numbers is odd but 270 is even.Ergo there are no three consecutive odd numbers that sum to 270.Three consecutive numbers that sum to 270 are 89, 90, 91.Three consecutive even numbers that sum to 270 are 88, 90, 92.
Any two consecutive numbers must comprise one odd and one even number, so their product must be even. Any three consecutive numbers must include two consecutive numbers so the result still applies.
There is no set of three consecutive even integers whose sum is 999. There are two other sets; one is odd, the other is mixed. The odd set is 331, 333 and 335. The mixed set is 332, 333 and 334.
As all the required numbers are even, we can identify the smallest value number as 2a, then the other three consecutive even numbers are (2a + 2), (2a + 4) and (2a + 6). The sum of these four numbers is, 2a + (2a + 2) + (2a + 4) + (2a + 6) = 8a + 12 Then, 8a + 12 = 412 8a = 412 - 12 = 400 2a = 400 / 4 = 100 The four consecutive even numbers are 100, 102, 104 & 106. NOTE : In this problem the choice of 'a' as the smallest value number would have achieved the correct answer but in other situations such a choice could have resulted in 4 consecutive ODD numbers being found. When in doubt use 2a or similar to clearly identify that the number is even.
No, it is impossible.
-998 = if its negative number 100 = if its positive numbers
The numbers are 40, 42 and 44.
The formula for this is x + (x+2) + (x+4) = 18 3x + 6 = 18 3x = 12 x = 4 So the three consecutive even numbers are 4, 6, and 8, which add up to 18.
-- method -- We need X numbers which are consecutive, so the middle number will be 1/ X of the total. Divide the sum of the numbers by the number of numbers ... in this case divide 186 by 3. The numbers are to be consecutive and even, so subtract 2 from the number go get one of the numbers and add 2 to the number to get the other number. You now have three numbers which are even and consecutive. Now, place a minus sign in front of them, to turn them into negative numbers For instance 12, 14 and 16 are three consecutive numbers whose sum is 42. -12, -14 and - 16 are three consecutive even integers whose sum is -42 Now you know all you need to solve the problem.
No other prime numbers are consecutive because there aren't any other even prime numbers.
10, 12, 14 are the consecutive even #'s that equal 36
The numbers are 244, 246 and 248.
The numbers are 52, 54 and 56.
The numbers are 22, 24 and 26.
There is only one pair of consecutive prime numbers, and the prime numbers are two and three, because any pair of consecutive numbers has one odd and one even number, and two is the only even prime number, because all other even numbers can be divided by two, and the only pairs of consecutive numbers are one and two and three, but one is not prime because it only has one factor, thus making the only consecutive pair of primes two and three. But the problem asks for the product of the two numbers, not the numbers themselves, so just multiply two and three together to get a final result of six.
3 consecutive numbers cannot be prime factors. Any three consecutive numbers would include at least one even number. The only even prime number is 2, and (2,3,4) doesn't qualify.
Call the smallest number x, which makes the next two consecutive even numbers x+2 and x+4. The sum of these three numbers is 36, so: x + (x + 2) + (x + 4) = 36 3x + 6 = 36 3x = 36 - 6 = 30 x = 10 So the three numbers are 10, 12, and 14, which indeed total 36. So the largest number is 14. Note that the question was about consecutive even numbers. Had the question just been about consecutive numbers, the numbers would be x, x+1, and x+2, so you'd get x + (x+1) + (x+2) = 36, 3x + 3 = 36, 3x = 33, x=11. The three numbers would be 11, 12, and 13, so the answer would be 13.
The three numbers will be 20, 22, and 24. 20 + 22 + 24 = 66
Suppose the smallest integer is A. The next two even numbers are A+2 and A+4. Using the information supplied we can form an equation: 2A - 14 = A + A+2 + A+4 Rearranging: 2A - 14 = 3A + 6 -20 = A So the three integers are -20, -18 and -16.