You can either do this by trial-and error, or solve the equation n + (n + 2) + (n + 4) = 48.
60.
The formula for this is x + (x+2) + (x+4) = 18 3x + 6 = 18 3x = 12 x = 4 So the three consecutive even numbers are 4, 6, and 8, which add up to 18.
The numbers are 244, 246 and 248.
The three numbers will be 20, 22, and 24. 20 + 22 + 24 = 66
276, 278 & 280.
The smallest is 14.
If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.If you take three consecutive odd (or three consecutive even) numbers, one of the three will always be a multiple of 3.
Thy are 8, 10 and 12.
The three consecutive even numbers with a sum of 138 are 44, 46 and 48.
60.
Type your answer here... Dertermine three consecutive even numbers who's sum is 42?
The formula for this is x + (x+2) + (x+4) = 18 3x + 6 = 18 3x = 12 x = 4 So the three consecutive even numbers are 4, 6, and 8, which add up to 18.
The numbers are 40, 42 and 44.
No, it is impossible.
The numbers are 244, 246 and 248.
The numbers are 52, 54 and 56.
The numbers are 22, 24 and 26.