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Solve the system of equations using the elimination method negative x plus y equals negative 3 and 3x plus 2y equals 9?
By elimination: x = 3 and y = 0
Xy plus 7 equals 22 where y equals 3?
its 5 because if y is 3 then u have to ask yourself wat times 3 + 7 is 22
What is -xy when x equals -8 and y equals 3?
When x equals -8 and y equals 3, the expression -xy becomes -(-8)(3). Multiplying -8 and 3 gives us -24. Therefore, -xy equals -24 in this scenario.
What is the answer to this math question 3xy-xy-2y plus 5y?
That equals 2xy + 3y which factors to y(2x + 3)
Which method would be best to solve x plus y equals 13 and -x plus y equals 3?
16
When p is eliminated in the system 2p plus 5q equals -4 -p -7q equals 11?
Solving by elimination: p = 3 and q = -2
Can You Solve 2x plus 3y equals 18 and 2x-3y equals -6 Using The Elimination Method?
Yes and it works out that x = 3 and y = 4
How do you solve 2xy plus 6 equals 4xyz for y?
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
How do you solve xy equals 3?
If you're solving for x, then x = 3/y.
4xy plus 1 equals 3y-7x solve for y?
4xy+1=3y-7x 4xy-3y=-7x-1 y(4x-3)=-7x-1 y=(-7x-1)/(4x-3)
How can you solve this elimination x plus 8y equals 3 2x plus 3y equals -7?
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
If xy equals x2 plus y2 plus 2xy?
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2
