(2,-2)
By elimination: x = 3 and y = 0
4
You cannot solve one linear equation in two variables. You need two equations that are independent.
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
(2,-2)
By elimination: x = 3 and y = 0
You can solve lineaar quadratic systems by either the elimination or the substitution methods. You can also solve them using the comparison method. Which method works best depends on which method the person solving them is comfortable with.
4
You cannot solve one linear equation in two variables. You need two equations that are independent.
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58
8840-026
Simultaneous equations can be solved using the elimination method.
the answer
One way to solve this system of equations is by using matrices. Form an augmented matrix in which the first 2x2 matrix is the coefficient matrix and the 2x1 matrix on its right is the answer. Now apply Gaussian Elimination and back-substitution. Using this method gives x=5 and y=1.
There are no disadvantages. There are three main ways to solve linear equations which are: substitution, graphing, and elimination. The method that is most appropriate can be found by looking at the equation.
Solve the following systems of simultaneous linear equations using Gauss elimination method and Gauss-Seidel Method 2x1+3x2+7x3 = 12 -----(1) x1-4x2+5x3 = 2 -----(2) 4x1+5x2-12x3= -3 ----(3) Answer: I'm not here to answer your university/college assignment questions. Please refer to the related question below and use the algorithm, which you should have in your notes anyway, to do the work yourself.