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0.25 meters per hour
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What is your speed in meters per second if you travel 203 kilometers in four hours and 48 minutes?
distance = rate * time rate = distance / time 1 kilometer = 1000 meters 4 hours and 48 minutes = 288 minutes * 60 seconds/minute = 17280 seconds 203 km * 1000 meters/km / 17280 seconds ~= 11.75 meters per second
How many meters per day would a snail travel if it did 80 meters in 20 hours?
There are 24 hours in a day. The snail travels 80 metres in 20 hours. If you divide the distance traveled by the number of hours taken (80 ÷ 20), then you would know that the snail travels at a rate of 4 metres per hour. Multiply the rate by the number of hours in a day and you see that:4 x 24 =96 metres per day
How do you use rate in a math sentence?
If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?If they travelled 350 miles in 7 hours, what rate of speed were they doing?
What is the speed of a cheetah that travels a total of 112 meters in 4 seconds?
Distance = Rate * Timeso,Rate(speed) = Distance/Time= 112 meters/4 seconds= 28 meters/second
How much time would be spent traveling 583 meters at 53 meters per second?
Distance = Rate X Time so, rearrange algebraically; Time = Distance/Rate = 583 meters/53 meters/s ( meters cancel ) = 11 seconds
In an experiment a snail was observed to have moved a distance of 0.5 meters in 2 hours what rate of movement was observed in this experiment?
0.25
In an experiment a snail was observed to have moved a distance of 0.5 meters in to hours what rate of movement was observed in this experiment?
0.5 m in 2 hours would be 1 m per hour.
Ask us anythIn an experiment a snail was observed to have moved a distance of 0.5 meters in 2 hours. What rate of movement was observed in this experimenting?
0.5 m in 2 hours would be 1 m per hour.
In an experiment a snail was observed to have moved a distance of 0.5 meters in 2 hours. What rate of movement was observed in this experiment?
In one hour the snail moved 0.25, therefore the speed was 0.25 per hour
What is rate of movement?
The rate of movement is speed.
What is your speed in meters per second if you travel 203 kilometers in four hours and 48 minutes?
distance = rate * time rate = distance / time 1 kilometer = 1000 meters 4 hours and 48 minutes = 288 minutes * 60 seconds/minute = 17280 seconds 203 km * 1000 meters/km / 17280 seconds ~= 11.75 meters per second
How many meters per day would a snail travel if it did 80 meters in 20 hours?
There are 24 hours in a day. The snail travels 80 metres in 20 hours. If you divide the distance traveled by the number of hours taken (80 ÷ 20), then you would know that the snail travels at a rate of 4 metres per hour. Multiply the rate by the number of hours in a day and you see that:4 x 24 =96 metres per day
How do you write 20 miles over 4 hours as a unit rate?
20 miles over 4 hours as a unit rate is written 5 miles per hour. 5 miles per hour is 2.235 m/s (meters per second).
What happens when a glaciers rate of melting is greater than its rate of movement?
An ice front recedes when a glaciers rate of melting is greater than its rate of movement. It is the end of the glacier.
What control the rate of movement of groundwater?
What controls the movement of groundwater
What is an unfavorable exchange rate?
unfavourable exchange rate movement
How fast are you travelling if you cover 22.03 meters in 3.8 seconds?
Distance = Rate * Time Manipulated algebraically, Rate = Distance/Time Rate = 22.03 meters/3.8 seconds = 5.8 meters per second =================
