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To do these problems the algebra way, make n the middle integer and call the 3 integers n-1, n, and n+1.
(n-1) + n + (n+1) = -93
simplifying the left side,
3n = -93
divide both sides by 3 to get n by itself ('isolate' n)
n = -31
So the 3 consecutive integers are -32, -31, and -30.
-32, -31, -30
What else can I help you with?
Three consecutive integers that have the sum of 96?
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
What are three consecutive integers whose sum is 96?
31 32 33
What are three consecutive integers with the sum of 96?
The numbers are 31, 32 and 33.
Find three consecutive integers whose sum is 96?
31, 32 and 33
Find three consecutive integers whose sum is negative 96?
-31, -32, -33
Find three consecutive even integers whose sum is 96?
Average is 96/3 ie 32 so integers are 30, 32 and 34.
What are two consecutive odd integers if their sum is 96?
The integers are 47 and 49.
What are four consecutive integers whose sum is 96?
They are odd consecutive integers: 21, 23, 25 and 27.
What is the sum of two even consecutive integers even to -194?
The integers are -98 and -96.
Three consecutive integers whose sum is 96?
To figure this out, divide 96 by three, ignoring the remainder for now. This gives the number 30. The remainder is 6. Three consecutive numbers that add up to six are 1, 2 and 3. So the three consecutive integers are 31, 32, and 33.
What 3 consecutive integers sum is 96?
31, 32, 33
What are three consecutive integers that have a sum of 96?
Divide 96 by 3= 32 your three numbers are now: 32 -1 = 31 32 = 32 32 + 1=33 31 + 32 +33 = 96
