What three consecutive integers have a sum of 96?

Answer 1

To do these problems the algebra way, make n the middle integer and call the 3 integers n-1, n, and n+1.

(n-1) + n + (n+1) = -93

simplifying the left side,

3n = -93

divide both sides by 3 to get n by itself ('isolate' n)

n = -31

So the 3 consecutive integers are -32, -31, and -30.
-32, -31, -30

Answer 2

find three consecutive integers whose sum is - 93

Answer 3

31, 32, 33