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What are three consecutive odd integers whose sum is 336?
The sum of any three consecutive odd integers is going to give an odd result. It is impossible for the sum of an odd number of odd integers to equal an even number.
How would you find four consecutive even integers whose sum is four?
You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.You can do this by trial-and-error. Or, give the lowest of the four consecutive integers a name, like "x". The three other integers will then be "x+2", "x+4", and "x+6". So, you have to solve the equation:x + (x + 2) + (x + 4) + (x + 6) = 4The answer is the lowest of the four consecutive even integers.
What are three consecutive even integers whose sum is 32?
That isn't possible; three consecutive integers, or three consecutive positive integers, always have a sum that is a multiple of 3. In general, you can solve this quickly by trial and error. In this case, you will quickly find that a certain set of three consecutive integers will give you a sum that is TOO LOW, while the next-higher even integers will give you a sum that is TOO HIGH. You can also write an equation and solve it: n + (n + 2) + (n + 4) = 32. If you solve it, you will find that the solution is fractional, not integral.
Find two consecutive integers such that the sum of the smaller and 3 times the larger is 330?
x + 3(x +1) = 330 4x = 327 which doesn't give an answer in integers. If question should read "consecutive ODD integers" the answer would be 81 and 83.
What are three consecutive integers of -363?
Your question is not well formed, but i assume you mean 3 consecutive integers that sum to -363. If that is the case solve the following equation: (n-1) + (n) + (n+1) = -363 to give you the middle integer.
How do you add two integers if the have different signs?
You subtract the smaller from the larger and give the answer the sign of the number with the larger absolute value.
The sum of three consecutive even integers that give you 151 and tha sum of three consecutive odd integers that give you 150?
There are no such answers. The sum of even numbers is even. The sum of odd numbers could be even, but the sum of three consecutive odd numbers is always odd. One could swap the questions to get potentially answerable questions: Sum of 3 consecutive EVEN integers = 150 48 + 50 + 52 = 150 unfortunately, we can already see that if we were to make these odd integers (add 1 to each), we would get 153, not 151. Sum of 3 consecutive ODD integers = 151 49 + 51 + 53 = 153 47 + 49 + 51 = 147 We can see that, whenever we slide our three consecutive integers up one, we raise the value of the sum up 3, and if we jump from odd to odd, or even to even, we raise each integer by 2, so we raise the sum by 6.
What is the rule for adding two integers that vary in sign?
Subtract the number with the smaller absolute value from the other. Give the answer the sign of the number with the larger absolute value.
What are the multiples of 126 but subtract to give you -12?
138
Find three even consecutive integers where the largest is 20 less than three times the smallest?
First, you give each integer a value. X or N are common. The integers would then be N, N + 2, N + 4.That would make 3(N) - 20 = N + 4. Subtract N from both sides and add 20, so you get:3N - N (=2N) - 20 + 20 = N - N + 4 + 20.That leaves you with 2N = 24, and if you divide both sides by 2, that gives you:N = 12.Thus, the three integers are:12, 14, 16
Give three sets having exactly two common elements.?
Integers in the range 0-10. Squares in the range 0-10. Cubes in the range 0-10. Common elements are {0,1}
Who do certain calculations involving integers give positive or negative answers?
Because different operations with different integers give different answers.
