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What is a two digit number that is divisible by both 6 and 9?
54
What is the largest two odd digit number divisible by 7?
98 is the largest two digit number divisible by 7.
What is the smallest two digit number that is divisible by both the sum and the product of its digits?
12
What numbers is divisible by both 9 and 4 5 digit?
A five-digit number that is divisible by both 9 and 4 must meet the criteria for divisibility by these numbers. A number is divisible by 9 if the sum of its digits is divisible by 9, and it is divisible by 4 if the last two digits form a number that is divisible by 4. The smallest five-digit number is 10,000, and the largest is 99,999; thus, any five-digit number that meets these criteria can be calculated by finding the least common multiple of 9 and 4, which is 36, and checking multiples of 36 within that range. For example, 10,008 is a five-digit number divisible by both 9 and 4.
What is a two digit number that is divisible by 6 and 9?
Here are two digit numbers that are divisible by both 6 and 9: 18 (which is the least common multiple) 36 54 72 90
What is the rule for a number that is divisible by 4?
If the last two digits are divisible by 4 then the number is divisible by 4. Thus, if the tens digit is even and the units digit is 0 or 4 or 8 OR if the tens digit is odd and the units digit is 2 or 6 then the number is divisible by 4.
A two digit number divisible by 10?
20.
How many two digit numbers are divisible by either 3 or 5?
How many two digit number are divisible by 5
What is the probability that a four digit number is divisible by 2?
Even numbers are divisible by two, and half of all numbers are even, so there is a 50 percent chance that a four-digit number is divisible by two.
How many two digit numbers divisible by neither 3 nor 5?
48.The first two digit number is 10, the last two digit number is 99, so there are 99 - 10 + 1 = 90 two digit numbers→ 10 ÷ 3 = 31/3 → first two digit number divisible by 3 is 4 x 3 = 12→ 99 ÷ 3 = 33 → last two digit number divisible by 3 is 33 x 3 = 99→ 33 - 4 + 1 = 30 two digit numbers divisible by 3→ 10 ÷ 5 = 2 → first two digit number divisible by 5 is 2 x 5 = 10→ 99 ÷ 5 = 194/5 → last two digit number divisible by 5 is 19 x 5 = 95→ 19 - 2 + 1 = 18 two digit numbers divisible by 5→ 30 + 18 = 48 two digit numbers divisible by 3 or 5 OR BOTH.The numbers divisible by both are multiples of their lowest common multiple: lcm(3, 5) = 15, and have been counted twice, so need to be subtracted from the total→ 10 ÷ 15 = 010/15 → first two digit number divisible by 15 is 1 x 15 = 15→ 99 ÷ 15 = 69/15 → last two digit number divisible by 15 is 6 x 15 = 90→ 6 - 1 + 1 = 6 two digit numbers divisible by 15 (the lcm of 3 and 5)→ 48 - 6 = 42 two digit numbers divisible by 3 or 5.→ 90 - 42 = 48 two digit numbers divisible by neither 3 nor 5.
What six digit number is only divisible by two?
There is no number, no matter the number of digits, that is only divisible by 2.
What two digit is divisible by 528?
None. The smallest number divisible by 528 is 528.
