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Q: What two numbers have the sum of 82 and the difference of 8?

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Suppose one of the numbers is x. Then, because they sum to 82, the other number is 82 - x. Then their difference gives the equation x - (82 - x) = 24 or 2x - 82 = 24

46 and 36

The numbers are -83 and -82.

106

Average of five numbers is 82 so their sum is 82*5 = 410. Average of four of them is 80, so their sum is 80*4 = 320. So the fifth number is 410 - 320 = 90.

41x2=82

69 + 18 = 67

No. 82 is divisible by two and also these numbers: 1, 41 and 82.

.82

82 is divisible by 41 and 2.

They are: 79+3 = 82

41

150 = 12 + 62 + 72 + 82

The numbers are 81, 82 and 83.

41x2

They are 2 and 41

2 and 41

The numbers are 81, 82 and 83. Also, 80, 82 and 84

The original number would be 28. Swapped around, the number's digits are 82. The difference between the two numbers is 54.

1 and 82 2 and 41

1 x 82, 2 x 41.

4205-4123 4246-4164 4328-4246 4205-4287 and 4287-4369

2, 41

100 = 62 + 82 = 82 + 62 and there is no other way

x = 59y = 23Let:x = the first numbery = the second numberx + y = 82 -- equation (1)x - y = 36 --- equation (2)By Elimination:x + y = 82x - y = 36=========2x = 118 2x/2 = 118/2x = 59x + y = 82y = 82 - xy = 82 - 59y = 23check:x - y = 3959 - 23 = 3636 = 36Let x = 1st numberlet y = 2nd numberX + Y = 82X - Y = 36add above equations2X = 118X = 59Y = 23