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If the sum of the digits in a two digit number is 10 and when the digits are reversed the new number is 54 more than the original number what is the original number?
Possibility of two digit no whose sum is 10
19,28,37,46,55,64,73,82,91
Now add 54 to each no mentioned above
73,82,91,100,109,118,127,136,145
See after 1st comma 28 and 82
Reverse of 28 is 82. That no 82 is 54 more than the no 28. So 28 is the original
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