A 30 degree angle is acute because it is greater than 0 but less than 90 degrees
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30o
The sum of 2 supplementary angles is 180o. If one is 30o, the other is 150o - 30o = 150o.
The arcsine is the angle whose sine is equal to the given value. arcsine is also called sine inverse (sin-1 ) if sin 30o = 1/2 , then sin-1 1/2 = 30o
It reflects at like 45 degrees I think. No, it reflects off at the same angle it hits the mirror. If the light wave hits the mirror at a 30o angle on the left side, it will reflect off at a 30o angle on the right side. Scientists usually measure these angles from an imaginary line perpendicular to the mirror at the point where the light wave hits the reflecting surface; sounds awkward, but it makes the math easier.
Type your answer here... 5.23
30o
The sum of 2 supplementary angles is 180o. If one is 30o, the other is 150o - 30o = 150o.
In a 30-60-90 triangle, the measure of the hypotenuse is two times that of the leg opposite the 30o angle. The measure of the other leg is SQRT(3) times that of the leg opposite the 30o angle.
30o
A complementary angle is the angle that would create a right angle when added on to the original angle. So, if you had an angle of 60o, the complementary angle would be 30o
The sine of the angle will be equal to the opposite side divided by the hypotenuse in a right triangle:sin (30o) = 12.5 m / hypotenusehypotenuse = 12.5 / sin (30o)hyp. = 12.5m/0.5hyp. = 25 meters
The arcsine is the angle whose sine is equal to the given value. arcsine is also called sine inverse (sin-1 ) if sin 30o = 1/2 , then sin-1 1/2 = 30o
No: The sum of the exterior angles of a polygon is 360o. For a dodecagon (12 sides) the exterior angle is 360o / 12 = 30o. The interior and exterior angles are supplementary and so they sum to 180o; thus the interior angle of a dodecagon is 180o - 30o = 150o. For an interior angle of 144o, the exterior angle is 180o - 144o = 36o, so there are 360o / 36o = 10 sides (a decagon).
Remember the sum of the 3 angles of a triangle = 180degrees Let angle 1 = x angle 2 = 2x angle 3 = x-20 Sum = x + 2x + x - 20 =180o 4x - 20 = 180o 4x = 200o x = 50o 2x = 100 o x - 20 = 30o angle 1 = 50o angle 2 = 100 o angle 3 = 30o
For certain angles, the answer is yes. For 30o to the horizontal (in the positive x direction), you need to measure the horizontal distance to be twice the vertical distance. For example, draw a triangle with a base length of 10cm and, at a right angle to the base, measure a height of 5cm. The angle to the horizontal (the smaller angle) will be 30o. (The opposite is true for the angle of 60o).
It reflects at like 45 degrees I think. No, it reflects off at the same angle it hits the mirror. If the light wave hits the mirror at a 30o angle on the left side, it will reflect off at a 30o angle on the right side. Scientists usually measure these angles from an imaginary line perpendicular to the mirror at the point where the light wave hits the reflecting surface; sounds awkward, but it makes the math easier.