Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. The second line is, in fact not a line because all you have is an expression, not a equation.
Depending on where the equality sign appears, the two lines could intersect at right angles of not.
4yx
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
Imagine that it is a square of a binomial.It would have to be of the form (X+Y)^2, where Y is some real number.Using the FOIL method, expanding the square should get you...X^2+XY+YX+Y^2, which you can simplify to X^2+2YX+Y^2.So, X^2+50X+100 = X^2+2YX+Y^2Y^2 must equal 100, and 2Y must equal 50.But, there's no value for Y like that, is there?
Assume we want to graph -2yx = 8. Divide both sides by -2x, so we have: y = -4/x This equation gives two hyperbolas, one in Quad. II and another in Quad. IV. You can graph the function by substituting each x value for the expression to determine the full coordinates of the points. Finally, plot them on the graph and connect them with a line.
If you mean: 2y = x-4 then y = 0.5x-2 whereas the slope is 0.5 or a 1/2 and the y intercept is -2
4yx
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "divided by", "equals", "squared", "cubed" etc. Please use "brackets" (or parentheses) because it is impossible to work out whether x plus y squared is x + y^2 or (x + y)^2.
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (eg x-squared = x^2).
Imagine that it is a square of a binomial.It would have to be of the form (X+Y)^2, where Y is some real number.Using the FOIL method, expanding the square should get you...X^2+XY+YX+Y^2, which you can simplify to X^2+2YX+Y^2.So, X^2+50X+100 = X^2+2YX+Y^2Y^2 must equal 100, and 2Y must equal 50.But, there's no value for Y like that, is there?
Assume we want to graph -2yx = 8. Divide both sides by -2x, so we have: y = -4/x This equation gives two hyperbolas, one in Quad. II and another in Quad. IV. You can graph the function by substituting each x value for the expression to determine the full coordinates of the points. Finally, plot them on the graph and connect them with a line.
If you mean: 2y = x-4 then y = 0.5x-2 whereas the slope is 0.5 or a 1/2 and the y intercept is -2
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The two equations are:x = 2 - 2yx² + 4y² = 4The points where the first meets the second are the values of x and y that simultaneously satisfy both equations:Substitute using (1) for x in (2) and solve the formed quadratic:x² + 4y² = 4→ (2 - 2y)² + 4y² = 4→ 4 - 8y + 4y² + 4y² -4 = 0→ 8y² - 8y = 0→ 8y(y - 1) = 0→ y = 0 or y = 1Substituting these values back into (1) gives:y = 0 → x = 2 - 2× 0 = 2 - 0 = 2y = 1 → x = 2 - 2× 1 = 2 - 2 = 0→ The line meets the curve at the points (2, 0) and (0, 1)
f ( x ) = (x-2)/(x-1)if y = (x-2)/(x-1)yx-y= x - 2yx-x= -2+yx(y-1)=y-2x = (y-2)/(y-1)so g ( x ) the inverse function is also (x-2)/(x-1)
First put in this form. Y = mX + c4X - 3Y - 12 = 04X - 3Y = - 12- 3Y = - 4X - 12Y = (4/3)X + 4===========Points are,(- 3, 0 ) and ( 0, 4 )You do not have the full question yet since this question has infinite answers.4x - 3y - 12 = 04x = 3y + 12If the question only gives this one equation, you can substitute any number into x to get a corresponding answer.Let's say x = 14(1) = 3y - 124 = 3y - 1216 = 3yy = 5.33 (3 sig fig)Suppose there is another part to this statement: 4x - 3y - 12 = 0 an 3x = 2y3x = 2yx = 2y/3 (choose either of the equations [3x = 2y, since it is easier] and separate either of the letters ["x"] from the other things [other letters and any numbers]Substitute x = 2y/3 into 4x = 3y + 124 (2y/3) = 3y + 128y/3 - 3y = 12-1y/3 = 12-y = 36y = -36Substitute y = -36 into 3x = 2y (easier)3x = 2(-36)3x = -72x = -24The interception point is (-24,-36). [note that 2 straights lines will either intercept on 1 point (most cases), never (parallel lines with same gradient) or infinite times (same line)]
X = 1st numberY = 2nd numberFacts given:X = 2Y (One number is equal to 2 times the second number)2X + 2Y = 20 (2 times the 1st number, plus 2 times the 2nd number is 20)Now we can easily find X and Y.We'll use a method called substitution to help us.Our first equation: X = 2Y is already solved for X. (it equals 2Y's!)So let's substitute x = 2y into the 2nd equation and find out what y is. Remember to use parenthesis!2x + 2y = 202(2y) + 2y = 204y + 2y = 206y = 20y = 20/6y = 10/3We found a number for Y, even though it is a fraction.Let's substitute it back into our 1st equation to figure out what x is.x = 2yx = 2(10/3)x = 20/3In order to check and see if x = 20/3 and y = 10/3, substitute both x and y into either equation. You pick!2x + 2y = 202(20/3) + 2(10/3) = 2040/3 + 20/3 = 2060/3 = 2020 = 20 (check)