How would you find x and y intercept in the problem 4x minus 3y minus 12 equals 0?

Answer 1

First put in this form. Y = mX + c

4X - 3Y - 12 = 0

4X - 3Y = - 12

- 3Y = - 4X - 12

Y = (4/3)X + 4

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Points are,

(- 3, 0 ) and ( 0, 4 )

You do not have the full question yet since this question has infinite answers.

4x - 3y - 12 = 0

4x = 3y + 12

If the question only gives this one equation, you can substitute any number into x to get a corresponding answer.

Let's say x = 1

4(1) = 3y - 12

4 = 3y - 12

16 = 3y

y = 5.33 (3 sig fig)

Suppose there is another part to this statement: 4x - 3y - 12 = 0 an 3x = 2y

3x = 2y

x = 2y/3 (choose either of the equations [3x = 2y, since it is easier] and separate either of the letters ["x"] from the other things [other letters and any numbers]

Substitute x = 2y/3 into 4x = 3y + 12

4 (2y/3) = 3y + 12

8y/3 - 3y = 12

-1y/3 = 12

-y = 36

y = -36

Substitute y = -36 into 3x = 2y (easier)

3x = 2(-36)

3x = -72

x = -24

The interception point is (-24,-36). [note that 2 straights lines will either intercept on 1 point (most cases), never (parallel lines with same gradient) or infinite times (same line)]