f ( x ) = (x-2)/(x-1)
if y = (x-2)/(x-1)
yx-y= x - 2
yx-x= -2+y
x(y-1)=y-2
x = (y-2)/(y-1)
so g ( x ) the inverse function is also (x-2)/(x-1)
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Given a function that is one-to-one and onto (a bijection), an inverse relationship is a function that reverses the action of the first function.A simple example to illustrate:if f(x) = x + 2, then g(x) = x - 2 is its inverse. fg(x) = x = gf(x).To find an inverse relationship of a function f(x)write y = f(x) as a function of xswap x and ymake the [new] y the subject of the formulathat is the inverse function.Going back to f(x) = x + 2write y = x + 2swap: x = y + 2make y the subject of the above equation: y = x - 2and so f'(x) is x - 2 where f'(x) represent the inverse of f(x).
To find the inverse of a function, you replace x with y and y with x. Here, y=2x-4 would become x=2y-4. Now, we solve for y. 2y=x+4. y=(x/2)+4, and that is the inverse equation.
It is a.
is it 4 inverse of mod 17 or whole inverse? Whole inverse do not make sence, so, ans for the q is 13.
Usually there is an inverse key or( tan -1 )key for this