f ( x ) = (x-2)/(x-1)
if y = (x-2)/(x-1)
yx-y= x - 2
yx-x= -2+y
x(y-1)=y-2
x = (y-2)/(y-1)
so g ( x ) the inverse function is also (x-2)/(x-1)
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Given a function that is one-to-one and onto (a bijection), an inverse relationship is a function that reverses the action of the first function.A simple example to illustrate:if f(x) = x + 2, then g(x) = x - 2 is its inverse. fg(x) = x = gf(x).To find an inverse relationship of a function f(x)write y = f(x) as a function of xswap x and ymake the [new] y the subject of the formulathat is the inverse function.Going back to f(x) = x + 2write y = x + 2swap: x = y + 2make y the subject of the above equation: y = x - 2and so f'(x) is x - 2 where f'(x) represent the inverse of f(x).
To find the angle whose sine is 0.083, you can use the inverse sine function (arcsin). In degrees, this would be approximately 4.78 degrees. In radians, it is around 0.0833 radians. Since the sine function is periodic, there are additional angles in different quadrants that also satisfy this condition.
To find the inverse of a function, you replace x with y and y with x. Here, y=2x-4 would become x=2y-4. Now, we solve for y. 2y=x+4. y=(x/2)+4, and that is the inverse equation.
It is a.
is it 4 inverse of mod 17 or whole inverse? Whole inverse do not make sence, so, ans for the q is 13.