Using 32 ft/sec2 as the acceleration due to gravity, it would be 0.0303.. miles per sec.
A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
Acceleration of gravity near the surface of the earth is 9.8 meters (32.2 feet) per second2. Downward velocity after 2 seconds = 19.2 meters (64.4 feet) per second.
the answer is 24-9 m/sec. yuor welcome
A freely falling Ball has the acceleration of 9.8 m/s/s so after 5 seconds its velocity will be: t=5s a=9.8m/s/s v=5s * 9.8m/s/s =49 m/s
-2.33 metres per second squared
500 metres per second.
96 feet per second
160 feet per second
128
The speed (magnitude of velocity) is always 9.8 meters per second (32.2 feet per second) greater than it was exactly one second earlier. If the object spent "N" seconds falling, then its speed (magnitude of velocity) is 9.8N meters per second (32.2N feet per second) greater at the bottom than it was at the top. The direction of velocity remains constant under the influence of gravity ... straight down.
Any change in the velocity of anything is known as 'acceleration'. In the case of a falling object near the Earth's surface, the direction of the velocity is constant, and its magnitude increases by 9.8 meters (32.2 feet) per second, every second.
19.6 meters per second
Impact velocity depends on the mass of the object and the height it falls from. It is the speed at which the acceleration due to gravity is maximized.
The force of gravity causes the falling object's velocity to grow in magnitude by 9.8 meters per second every second, while its direction remains constant.
A falling object accelerates at a rate of 9.8 m/s2. That means that for every second that it is falling, its velocity increases by 9.8 m/s. The higher that the object is falling from, the longer it will have to speed up, thus the higher its velocity upon impact will be. (This is assuming that it does not reach terminal velocity, the velocity at which an object can no longer accelerate because it is travelling so fast that the drag force (air resistance) is equal to the force of gravity.)
32 feet / second / second. Calculating the velocity of an object falling due to gravity is a complicated process because gravity decreases the further above the Earth you go. There is also a terminal velocity because of the viscosity of the air. Simply though, acceleration due to gravity at the Earth's surface is roughly 9.8m/s2. This means, after 1 second, an object will have achieved a velocity of 9.8m/s. The equation then if the viscosity of air and height above the Earth's surface are ignored is V = 9.8 x S Where V is the velocity and S is the number of seconds it has been falling.
the answer to this question can be found using the following simple equation:Vf = 9.8t + ViVf = Velocity Final (m/s)Vi = Velocity Initial (m/s)t = Time (s)For your specific problem, providing the object wasn't moving at the start of the 4 second period, the answer is 39.2 meters per second.