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Q: What volume of 0.140 solution is required to completely react with 125 of 0.140?
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How do you find the volume of a three-dimensional irregular shape?

If it is a small shape that is denser than a convenient fluid and insoluble in it and also does not react with it then the displacement method is simplest. Fill a graduated cylinder with the fluid, measure the volume of the fluid. Then gently insert the shape and measure the apparent volume of the fluid. The difference between the two volume readings is the volume of the shape. If the shape is less dense than the fluid you have to make one change. You need to find a dense insoluble object. Measure the volume of the fluid with the dense object immersed in it. Then measure the volume when the dense object and the shape are joined together and submerged. The difference between the two measures is the volume of the shape. This method will not work with soluble shapes unless you can find a fluid that it is not soluble in. Similarly, you cannot use a fluid that will react. So measuring the volume of a lump of sugar or a lump of sodium using water are non-starters. Finally, the method will not work if the irregular shape is huge.


How do you calculate the volume of an irregular 3D object if you know the surface area of one side and the height?

If the object is irregular you have no hope of calculating its volume from any known dimensions. The easiest way to find its volume is to fill a container full of a liquid (with which the object will not react). Submerge the object in the liquid and collect the liquid displaced. The volume of the displaced liquid, which should be easily measurable, will be the same as that of the object.


How many liters of water are needed to react with 2L of oxygen to make water?

Water does not need to react with oxygen to make water!


How do a positive and a negative particle react?

Violently


How do positive and negative particles react?

They attract

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2 HCl + CaCO3 = CaCl2 + CO2 + H2O Therefore it takes twice as many moles of HCl to react with CaCO3 Mol CaCO3 = mass / formulae weight = 10 / 40.08 + 14.01 + 3(16.00) = 10 / 102.09 = 0.0980 mol Mol HCl = 2 x 0.0980 = 0.1959 mol Volume HCl = mol / c = 0.1959 / 0.10 = 1.9591 L Volume required to react of HCl = 1.9591 L


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