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How do you find the volume of a three-dimensional irregular shape?
If it is a small shape that is denser than a convenient fluid and insoluble in it and also does not react with it then the displacement method is simplest. Fill a graduated cylinder with the fluid, measure the volume of the fluid. Then gently insert the shape and measure the apparent volume of the fluid. The difference between the two volume readings is the volume of the shape. If the shape is less dense than the fluid you have to make one change. You need to find a dense insoluble object. Measure the volume of the fluid with the dense object immersed in it. Then measure the volume when the dense object and the shape are joined together and submerged. The difference between the two measures is the volume of the shape. This method will not work with soluble shapes unless you can find a fluid that it is not soluble in. Similarly, you cannot use a fluid that will react. So measuring the volume of a lump of sugar or a lump of sodium using water are non-starters. Finally, the method will not work if the irregular shape is huge.
How do you calculate the volume of an irregular 3D object if you know the surface area of one side and the height?
If the object is irregular you have no hope of calculating its volume from any known dimensions. The easiest way to find its volume is to fill a container full of a liquid (with which the object will not react). Submerge the object in the liquid and collect the liquid displaced. The volume of the displaced liquid, which should be easily measurable, will be the same as that of the object.
Why cromate can easily be converted to dicromate?
Chromate (CrO4^2-) can easily be converted to dichromate (Cr2O7^2-) due to the change in pH of the solution. In acidic conditions, chromate ions react with hydrogen ions (H+) to form dichromate ions. This equilibrium is influenced by the concentration of hydrogen ions, which shifts the balance toward dichromate formation in lower pH environments. Thus, the conversion is a simple acid-base reaction dependent on the acidity of the solution.
How many liters of water are needed to react with 2L of oxygen to make water?
Water does not need to react with oxygen to make water!
How do positive and negative particles react?
They attract
How many milliliters of a 0.270 M solution are needed to react completely with 3.245 g of oxalic acid?
To determine the volume of 0.270 M solution needed to react completely with 3.245 g of oxalic acid, first calculate the number of moles of oxalic acid (by dividing the mass by its molar mass). Then, use the mole ratio between the acid and the solution (from the balanced chemical equation) to find the moles of solution required. Finally, use the molarity to calculate the volume using the formula: volume (in liters) = moles / molarity. Convert the volume to milliliters, if needed.
What volume of 0.100 M HCl is required to completely react with ml of 0.161 M Na2CO3?
To solve this problem, we need to use the balanced chemical equation between HCl and Na2CO3. From the equation, we can see that it is a 1:2 ratio for HCl to Na2CO3. Therefore, we need twice the volume of 0.161 M Na2CO3 to react completely with HCl. Calculate the volume of HCl required by multiplying the volume of Na2CO3 by 2.
Which quantity is directly measured in a titration?
The volume of titrant required to reach the equivalence point is directly measured in a titration. This volume corresponds to the amount of titrant needed to completely react with the analyte in the sample.
What volume of 0.176M Na3PO4 solution is necessary to completely react with 91.3mL of 0.115M CuCl2?
To determine the volume of the Na3PO4 solution needed for complete reaction, we would first write a balanced chemical equation for the reaction between Na3PO4 and CuCl2. Then, use the molarity of CuCl2 and the stoichiometry of the reaction to calculate the volume of Na3PO4 required.
What volume of .25M cobalt(III) sulfate is required to react completely with 25 mL of .0315M calcium hydroxide?
To determine the volume of .25M cobalt(III) sulfate required to react completely with 25 mL of .0315M calcium hydroxide, you need to write and balance the chemical equation for the reaction. Then, use the stoichiometry of the balanced equation to determine the amount of cobalt(III) sulfate needed based on the moles of calcium hydroxide used in the reaction. Finally, use the concentration of cobalt(III) sulfate to calculate the volume needed.
What volume in ml of a 0.03455 M calcium hydroxide solution would be needed to completely react with 32.76 ml of a 0.0215 M phosphoric acid solution?
To find the volume of calcium hydroxide solution needed to react with the phosphoric acid solution, you need to determine the mole ratio between calcium hydroxide and phosphoric acid. The balanced chemical equation for the reaction will guide you in calculating the amount needed. Once you have the mole ratio, you can use the concentrations and volumes of the solutions to determine the volume of calcium hydroxide needed.
What is the significance of molarity titration in determining the concentration of a solution?
Molarity titration is important because it allows for the precise determination of the concentration of a solution by measuring the volume of a known concentration solution needed to react completely with the unknown solution. This method is widely used in chemistry labs to accurately measure the concentration of various substances.
What is a standard solution and how is it used in titration?
A standard solution is a solution with a known concentration of a substance. In titration, a standard solution is used to determine the concentration of another substance by reacting the two solutions until a chemical reaction reaches completion. The volume of the standard solution needed to react completely with the unknown solution is used to calculate the concentration of the unknown substance.
How many milliliters of a 2.00 M solution of hydrochloric acid are needed to completely react with 75.0 g of iron sulfide according to the chemical reaction shown below?
To determine the volume of 2.00 M HCl needed to completely react with 75.0 g of iron sulfide, we first write and balance the chemical equation. FeS + 2HCl → FeCl2 + H2S. Then, calculate the number of moles of FeS (75.0 g / molar mass of FeS) and use the mole ratio from the balanced equation to find the moles of HCl needed. Finally, use the definition of molarity to determine the volume of HCl solution required.
What volume in drops of 16M HNO3 is required to react with 0.0214grams of Cu metal?
To find the volume of 16M HNO3 required to react with 0.0214g of Cu metal, you need to calculate the moles of Cu. Then, using the balanced equation for the reaction between Cu and HNO3 (Cu + 4HNO3 → Cu(NO3)2 + 2NO2 + 2H2O), you can determine the moles of HNO3 needed. Finally, using the molarity of the HNO3 solution, you can calculate the volume in drops.
What volume of a 0.10 mol dm-3 solution of HCl is required to react with 10.0 g of CaCO3?
2 HCl + CaCO3 = CaCl2 + CO2 + H2O Therefore it takes twice as many moles of HCl to react with CaCO3 Mol CaCO3 = mass / formulae weight = 10 / 40.08 + 14.01 + 3(16.00) = 10 / 102.09 = 0.0980 mol Mol HCl = 2 x 0.0980 = 0.1959 mol Volume HCl = mol / c = 0.1959 / 0.10 = 1.9591 L Volume required to react of HCl = 1.9591 L
What mass of oxygen (O2) is required to react completely with 86.17 grams of C6H14?
The answer is 152 g oxygen.
