The question is impossible to answer.
Add heat and you get combustion.
Oxygen, heat and fuel :)
It's the oxygen. Since oxygen doesn't dissolve into nitrogen - air is a mixture, not a solution - you can't call it the solute and the nitrogen the solvent, which may have been the answer you thought you were going to get.
A mixture of gases that strongly resembles the major components of earth's atmosphere.
For complete proper combustion of Propane: C3H8 + 5O2 = 3CO2 + 4H2O The relative atomic weights of a molecule of Propane and Oxygen are: Propane: 3 × C + 8 × H = 3 × 12 + 8 × 1 = 44 Oxygen: 2 × O = 2 × 16 = 32 Thus a molecule of propane is 44/32 = 1⅜ times heavier than a molecule of oxygen; and the same amount (number of molecules) of propane as 24 g of oxygen is 24g × 1⅜ = 33g Each propane molecule takes 5 oxygen molecules, thus: 33 g ÷ 5 = 6 3/5 g = 6.6 g If the combustion produces the poisonous carbon monoxide instead of carbon dioxide: 2C3H8 + 7O2 = 6CO + 8H2O → propane = 33g × 2/7 = 9 3/7 g ≈ 9.4 g A complete answer is thus between 6 3/5 g (6.6g) and 9 3/7 g (9.4 g) depending upon how much carbon monoxide relative to carbon dioxide is produced by the burning - the safe amount is 6.6 g.
Oxygen is a required reactant in a combustion reaction - without oxygen, you do not have combustion. If you combine a hydrocarbon with oxygen and add heat, you will cause a combustion reaction that results in carbon dioxide and water being formed (provided there was complete combustion).
No, oxygen is required for combustion to take place.
More oxygen is used in a complete combustion.
No. Oxygen is required for combustion. Mercury is not involved.
in complete combustion the amount of oxygen is higher/more than the amount of oxygen in incomplete combustion. Heat needs oxygen.
oxygen
Complete combustion of a hydrocarbon yields carbon dioxide & water; incomplete combustion yields carbon monoxide & water. By having excess oxygen you have enough oxygen to ensure complete combustion. For example the combustion of methane (CH4):complete combustion: CH4 + 2O2 --> CO2 + 2H2Oincomplete combustion: CH4 + 1.5O2 --> CO + 2H2OAs you can see you need a 1/2 mole less of oxygen for the incomplete combustion of methane. So as long as you have twice the amount (in terms of moles) of oxygen as methane you will ensure complete combustion. So anything in excess of that will also ensure complete combustion.
No moles of oxygen are produced by complete combustion of propane. Oxygen is CONSUMED, not produced. For combustion of 4 moles of propane, it will use 20 moles of oxygen.
what is the mass in grams of oxygen, is needed to complete combustion of 6 L of methane?
Oxygen is the required gas that is necessary for combustion
burning in oxygen ensures complete combustion
Propane is C3H8 and the combustion equation is C3H8 + 5O2 ==> 3CO2 + 4H2OSo the complete combustion of 1 mole of propane requires 5 moles of oxygen.