Almost exactly 100.00 mL.
Volume percent (v/v %) is defined as: volume percent = [(volume of solute) / (volume of solution)] x 100% Volume percent is handy when preparing solutions of liquids. Concentration of a solution can be stated in volume percentages. Be aware that volume of solution is in formula denominator, not volume of solvent. Thus to get 10% v/v solution of ethanol in water you can take 10 ml of ethanol and add enough water to have total 100 ml of resulting solution. It is worth to mention volumes of solute and solvent cannot be simply added to get volume of solution. For instance if you add 10 ml of ethanol to 90 ml of water the volume of the solution will be less than 100 ml.
The volume of an object can be determined by the displacement of water. By dropping the object into a measuring container of water, where the volume of the water is known, the object's volume can then be calculated by subtracting the volume of the water by the volume of the water and object combined.
The amount of water displaced by the block is the volume of the block. so (volume of water with block in it)-(original volume of water)= volume of block
the volume of water means CA
The volume of displaced water for a metal cylinder with a volume of 50cm3 is: 13,210 US gallons of water or 11,000 UK gallons of water.
The 1000 grammes of ethanol will occupy a greater volume because its specific gravity is lower than that of water. s.g. water = ~1.0 s.g. ethanol = ~ 0.794
It is prepared by taking five volume of ethanol and dissolve in 100 ml of water .
Hydrogen bonds are formed between water and ethanol molecules, the solution become more "packed"; the density increase and the volume decrease.
you would think 40ml but it is slightly less. 40 x 98% = 39.2ml when ethanol and water mix they are 98% of the volume
Percent by Volume of Solute in Solvent = Volume Solute/ (Volume Solvent + Volume Solute) * 100% = 48/ 192 = 25%
there the same.
Find the volume of the 100% ethanol Add 1/19 of water to the volume (if it is like 190ml, add 10ml of water since 190/200=95%)
Benzene or cyclohexane can be used in ethanol-water separation in order to allow distillation of ethanol past the azeotrope point (96.5% ethanol by volume). Of course the benzene (a known carcinogen) must be separated from the water before the water can be disposed. Fuel grade ethanol is often separated from water using molecular sieves. In this kind of separation water is entrained in "beads" which absorb water but reject ethanol. These are eventually regenerated for reuse.
The mole fraction and molality of ethanol -C2H5OH in an aqueous solution that is 45.0 percent ethanol by volume and the density of water is 1.00g per mL that of ethanol is 0.789 grams per mL and 70/18. A mole fraction in chemistry is the amount that is divided by the total amount of all constituents.
most "absolute" ethanol used in the lab is 95% ethanol by volume,this is due to the fact the ethanol is very miscible with water so its difficult to remove all the water that is present in the atmosphere,it is possible to get 100 alcohol but it is an awkward process and generally 95 does the job just fine
No because they have different densities so the volume of the two combined will be slightly less.
No, they are not additive. For example, 1 ml of water added to 1 ml of ethanol will not equal 2 ml total volume.