Use Pythagoras' theorem:
82+52 = 89 and the square root of this is 9.433981132 cm
5 x 10 = 50cm2
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
Perimeter of rectangle: 5+3+5+3 = 16cm
5*3 = 15 square cm
5cm x 2cm=10cm²A=10cm²
5 x 10 = 50cm2
Use Pythagoras's theorem -- c2=a2+b2, where a and b are sides of a rectangle, and c is the diagonal. Here, a = 5 [cm] and b = 10 [cm] So, c = sqrt (52 + 102) = 11.18 [cm] (<-- the negative root can be ignored) ===========================================
Perimeter of rectangle: 5+3+5+3 = 16cm
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
5*3 = 15 square cm
the perimeter of a rectangle with two 5cm squares will be 30cm
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
5cm x 2cm=10cm²A=10cm²
Area of a rectangle= Length * width Length= 5cm Width= 1cm Area=5cm *1cm =5cm2
12.5cm
The perimeter is the sum of the four sides. In this case, two sides have 14 cm each, and the other two sides have 5 cm eacn.
The perimeter is the total distance around the outside of a 2D shape. You calculate it by adding all the lengths of the sides together.So, for example.If I had a rectangle, the length was 11cm, and the width was 5cm.To work out the perimeter of this rectangle, I would simply add all the sides together. So, 11cm+11cm+5cm+5cm=33cmSimple! Hope I helped!