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What will be time period of simple pendulum at the centre of the earth?
Wiki User
∙ 12y ago
at the center of the earth, simple pendulmn has not any gravitational force(if we thought,the earth is an etended object) so at the center the gravitational acceleation is about 'zero' and that's why pendulumn's time period is 'infinite'.
Wiki User
∙ 12y ago
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What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
How would the period of a simple Pendulum be charged if the pendulum were moved from sea level to the moon?
The period is not likely to be charged. However, it would change due to the weaker gravitational force on the moon. Since the surface gravity of the moon is 0.165 that of the earth, the period would increase by a multiple of 1/sqrt(0.165) = 2.462 approx.
What is effect on time period of simple pendulum at centre of earth?
At the center of the Earth there would be no effective gravity; a pendulum wouldn't work as a pendulum.
What is the time period of simple pendulum at the center of the earth?
Infinite
What will be the time period of a simple pendulum at the centre of Earth?
Gravitational acceleration increases ,as distance from the centre decreases g=GM/s2 where, G=gravitational constant(6.67by 10^-11) M=mass of any pulling body(earth) s=distance from centre Though not infinite for the earth(is infinite for black hole) but the value of 'g' and hence, gravity is very high at the centre of the earth(6000 km below us), so a pendulum will swing very very fast at centre and its time period will be nearly zero T2=4(3.142)2l/g ================================= The centre of the Earth is occupied by solid material. A pendulum could not swing at that location. Also at the very centre of the earth all the mass is uniformly outside your location - there is no effective down position, so if you created a void to swing the pendulum it would not swing.
What is the time period of simple pendulum at center of earth?
i think it is infinite because acceleration due to gravity at the center of the earth is zero and time period of the simple pendulum is given by 2*3.14*sqrt(l/g)....
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
How does accelaration due to gravity effect the time period of a simple pendulum?
Normally the acceleration of gravity is not a factor in the period of a simple pendulum because it does not change on Earth, but if it were to be put on another celestial body the period would change. As gravity increases the period is shorter and as the gravity is less the period is longer.
What is the period of a simple pendulum 45 cm long on the Earth?
For small amplitudes, the period can be calculated as 2 x pi x square root of (L / g). Convert the length to meters, and use 9.8 for gravity. The answer will be in seconds. About 1.4 seconds.
How the motion of simple pendulum is affected if it is placed at the center of earth?
If the plumb point of a pendulum is the center of earth, the pendulum will make diametrical oscillations
If the period of a pendulum on Earth is 1.8 seconds what is the length of the pendulum?
Approx 80.5 centimetres.
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
