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What will be time period of simple pendulum at the centre of the earth?
Wiki User
∙ 12y ago
at the center of the earth, simple pendulmn has not any gravitational force(if we thought,the earth is an etended object) so at the center the gravitational acceleation is about 'zero' and that's why pendulumn's time period is 'infinite'.
Wiki User
∙ 12y ago
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What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
How would the period of a simple Pendulum be charged if the pendulum were moved from sea level to the moon?
The period is not likely to be charged. However, it would change due to the weaker gravitational force on the moon. Since the surface gravity of the moon is 0.165 that of the earth, the period would increase by a multiple of 1/sqrt(0.165) = 2.462 approx.
What is effect on time period of simple pendulum at centre of earth?
The time period of a simple pendulum at the center of the Earth would be constant and not depend on the length of the pendulum. This is because acceleration due to gravity is zero at the center of the Earth, making the time period independent of the length of the pendulum.
What is the time period of simple pendulum at center of earth?
The time period of a simple pendulum at the center of the Earth would theoretically be zero because there is no gravitational force acting on it. A simple pendulum's period is determined by the acceleration due to gravity, which would be zero at the center of the Earth.
What will be the time period of a simple pendulum at the centre of Earth?
The time period of a simple pendulum at the center of Earth would be ∞ (infinity). This is because the gravitational force is acting equally in all directions and there would be no net force to cause the pendulum to oscillate.
Can you conduct simple pendulum experiment at the centre of the earth?
It would not be possible to conduct a simple pendulum experiment at the center of the Earth due to extreme heat and pressure conditions. Additionally, the gravitational force at the center of the Earth would be effectively zero, which is essential for the functioning of a simple pendulum.
How does altitude from the surface of earth affect the period of a simple pendulum?
The period of a simple pendulum is not affected by altitude from the surface of the Earth, as it is determined by the length of the pendulum and acceleration due to gravity, both of which are constant at different altitudes within reasonable ranges.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
What is the time period of simple pendulum at the center of the earth?
The time period of a simple pendulum at the center of the Earth would be almost zero. This is because there is no gravitational force acting at the center of the Earth due to a balanced pull in all directions. Thus, the pendulum would not experience any acceleration and would not oscillate.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
What is the difference in period for a pendulum on earth and a pendulum on moon?
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity. Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the period of a simple pendulum 45 cm long on the Earth?
The period of a simple pendulum can be calculated using the formula T = 2π * sqrt(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. On Earth, the value of g is approximately 9.81 m/s^2. Converting the length of the pendulum to meters (0.45 m), the period would be about 1.42 seconds.
What is the period of a simple pendulum 80 cm long a on earth and b when it is in a freely falling elevator?
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
