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What is the difference in period for a pendulum on earth and a pendulum on moon?
Wiki User
∙ 13y ago
The period of a simple pendulum swinging at a small angle is approximately 2*pi*Sqrt(L/g), where L is the length of the pendulum, and g is acceleration due to gravity.
Since gravity on the moon is approximately 1/6 of Earth's gravity, the period of a pendulum on the moon with the same length will be approximately 2.45 times of the same pendulum on the Earth (that's square root of 6).
Wiki User
∙ 13y ago
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What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
Time period of a pendulum on moon is?
About 40.7% of that on Earth or about 2.46 times slower.
Is a pendulum's time period increases or decreases when it taken from earth to moon?
Increases.
How would the period of a simple pendulum be affected if it were located on the moon instead of the earth?
The period of a simple pendulum would be longer on the moon compared to the Earth. This is because the acceleration due to gravity is weaker on the moon, resulting in slower oscillations of the pendulum.
How would the time period of a simple pendulum clock be affected if it were on the moon instead of the earth?
The time period of a pendulum would increases it the pendulum were on the moon instead of the earth. The period of a simple pendulum is equal to 2*pi*√(L/g), where g is acceleration due to gravity. As gravity decreases, g decreases. Since the value of g would be smaller on the moon, the period of the pendulum would increase. The value of g on Earth is 9.8 m/s2, whereas the value of g on the moon is 1.624 m/s2. This makes the period of a pendulum on the moon about 2.47 times longer than the period would be on Earth.
Can you use simple pendulum in moon?
Yes. The period of the pendulum (the time it takes it swing back and forth once) depends on the length of the pendulum, and also on how strong gravity is. The moon is much smaller and less massive than the earth, and as a result, gravity is considerably weaker. This would make the period of a pendulum longer on the moon than the period of the same pendulum would be on earth.
What is the time period of a pendulum on moon?
... dependent on the length of the pendulum. ... longer than the period of the same pendulum on Earth. Both of these are correct ways of finishing that sentence.
What is the length of a pendulum whose period on the moon matches the period of a 1.94-m-long pendulum on the earth?
Nice problem! I get 32.1 centimeters.
Is a pendulum's time period increases or decreases when it taken from earth to moon?
Increases.
Time period of a pendulum on moon is?
About 40.7% of that on Earth or about 2.46 times slower.
Does the period of a pendulum increase or decrease on Moon?
The period of a pendulum (for short swings) is about 2 PI (L/g)1/2. The gravity on the moon is less than that on Earth by a factor of six, so the period of the pendulum on the moon would be greater, i.e. slower, by about a factor of 2.5.
Time period of simple pendulum is three seconds the same pendulum taken at the moon - what will be its new time period?
This pendulum, which is 2.24m in length, would have a period of 7.36 seconds on the moon.
What effect does the acceleration due to gravity on the moon have on a simple pendulum?
The lower acceleration due to gravity on the moon causes a simple pendulum to swing more slowly compared to Earth. The period of the pendulum is longer on the moon because gravity plays a role in determining the speed at which the pendulum swings back and forth.
If a simple pendulum with a period of 1 second is set in motion of the moon what is the new period of this pendulum?
The equation is: http://hyperphysics.phy-astr.gsu.edu/HBASE/imgmec/pend.gif T is the period in seconds, L is pendulum length in cm, g is acceleration of gravity in m/s2. We know on earth the period is 1s when the acceleration of gravity is 9.8m/s2, so the pendulum length is 24.824cm. The acceleration of gravity on the moon is 1.6m/s2. Substitute 24.824cm for L and 1.6 for g and you yield 2.475 seconds. The period is 2.475 seconds.
A pendulum has a period on the earth of 1.35 s What is its period on the surface of the moon where g equals 1.62 meters per second squared?
The period of a pendulum is given by T = 2π√(L/g), where L is the length of the pendulum and g is the acceleration due to gravity. Since the pendulum's length and mass do not change, its period on the moon would be T = 2π√(L/1.62), assuming the pendulum is the same length. Solving for T gives 2.56 seconds.
