xy = 50
if any number is said to be divisible by 5.... it means that when you divide that number by 5, the remainder will be equal to 0.... Eg: 125/5=0 so.... 125 is divisible by 5.......
250 is divisible by 1, 2, 5, 10, 25, 50, and 250.
YES!!!! Add the digits , if they sum to '9' then it is divisible by '9'. 1125 ' 1+ 1 +2 + 5 = 9 Hence 1125 is divislble by '9' 1125/ 9 = 125 The answer
Dividing 125 by 3 does not give an integer result. The sum is equal to 41.6 recurring (that is, 41.6666... or 41 and two thirds).
xy + xy = 2xy
125 is divisible by 5 but not by 10 unless you want an answer as a decimal
No. Ten is not evenly divisible by 125.
625 Is divisible by 5
256 125 is not a multiple of 4 so is not divisible by 4 without a remainder.256 125 ÷ 4 = 64031.25
12,500
43,750
yes! 15.625
Yes, but you wont get an integer. 120 and 135 are divisible to an integer.
A direct variation is when the value of K in multiple proportions is all divisible by the same number for example: XY=(1)(10) K=10 XY=(2)(20) K=40 XY=(3)(30) K=90 XY=(4)(40) K=160 In this situation the constant (K) of each proportion is divisible by 10 making the multiple equations a direct variation.
if any number is said to be divisible by 5.... it means that when you divide that number by 5, the remainder will be equal to 0.... Eg: 125/5=0 so.... 125 is divisible by 5.......
125 if you include 1000.
It could be: x*y = 20 and so 523*20 = 10460 which is divisible by 4 and 5 with no remainders