xy + xy = 2xy
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xy + x + y + 1 = (x + 1)(y + 1).
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
(x-y) + (xy - 1) = (x - 1)(y + 1)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
Yes