xy + x + y + 1 = (x + 1)(y + 1).
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
The only common factor to all terms is yz. → xy³z² + y²z + xyz = yz(xy²z + y + x)
(x-y) + (xy - 1) = (x - 1)(y + 1)
yes, it's the same, the answer will still be xy.
It is an expression in the form of: xy+7
It is an expression in the form of: xy+7
xy + x + y + 1 = (x + 1)(y + 1).
2+2y+x+xy=(x+2)(y+1)
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
xy plus 2x plus 4y plus 8 or (xy+2x) + (4y+8) or x(y+2) + 4(y+2) or (x+4)(y+2)
6y-18+xy-3x its impossible to do anything to it
x+xy=8 xy=-x+8 y=-1+8/x
x3+xy-x2y2=x(x2+y-xy2)
xy + y = z xy = z - y (xy)/y = (z - y)/y x = (z - y)/y
mid point of xy
The multiplicative inverse of 5y -xy + 1 is 1/5y -xy + 1 The additive inverse of 5y - xy + 1 is -5y + xy - 1