If you take out too much power, the generator will probably get damaged. In the best of cases, it has a built-in protection, and shuts down before it gets damaged. In any case, you should avoid taking out more power than the generator can handle; also, you should get a more powerful generator. Or reduce your use.
4core*240mm square..
It could be as much as 63 kW (63,000 Watts) into a load with a power factor of 1.0. For other loads, multiply the kVA by the power factor.
Yes, you can use both, but watts is more useful; it provides the total amount of power the generator can output.
The capacitor size for a 5 kVA generator typically depends on the power factor and the specific application. A general rule of thumb is to use about 0.5 to 1 microfarad (μF) of capacitance per kVA for power factor correction. Therefore, for a 5 kVA generator, you might consider a capacitor size ranging from 2.5 μF to 5 μF. However, it's essential to consult with a professional or refer to the generator's specifications for precise requirements.
To answer this question a voltage must be given to find the current output. Also whether the generator is three phase or single phase.
To calculate the output amps of a 600kVA generator at 240V, you would use the formula Amps = kVA / Volts. In this case, it would be 600kVA / 240V = 2500 amps.
The fuel consumption of a 250 kVA generator typically ranges from 10 to 15 liters per hour, depending on the load and efficiency. Therefore, over a 24-hour period, it would consume approximately 240 to 360 liters of fuel. For a more accurate estimate, it's best to refer to the specific generator's manual or specifications.
As a basic requirement in considering genset noise reduction -- Is the capacity of selected kVA size was enough for the load intended due to deration? The following are the normal practice: 1. Sound Attenuator (Industrial type muffler/silencer) 2. Soundproof Canopy - considered also as weatherproof for outdoor use 3. Soundproof Enclosure (Container Type)
The first thing that is required is the amperage of the motor. I = HP x 746/1.73 x E x %eff x pf. This comes to about 277 amps. The second formula to use to find KVA is KVA = I x E x 1.73/1000 = 277 x 480 x 1.73/1000 = 230. The minimum size generator will be 230 KVA.
Oh, dude, you're asking me about capacitors now? Like, I'm just a comedian, not an electrician. But hey, if you're looking for a capacitor for your 5 kVA generator, you probably want one with a capacitance rating that can handle the load and voltage requirements. Maybe check with an expert to get the right one, unless you want your generator to start spewing sparks like a Fourth of July fireworks show.
A volt-amp (va) is the same as a watt (w). A 2.8 kva generator can provide 2800 w of power which is more than sufficient for a 1000 w saw, as long as the safety circuit breaker on the generator can handle the load. Short answer, yes.
if you have 200 kva so it's 160 KW then ,you need 400 A MCCB and setting at 0.9 and use cable 4c.185 mm2 if the SMDB is nearby and all this will be change according to the ambient temperature and the electrical code used in your area