x = (-1 ± √11) / 2
2x2 + 11x + 15 = (x + 3)(2x + 5).
2x2=4x4=16
There are no powers e.g 2x2 would be due to the 2
5x^(2) + 2x - 4 = 2x^(2) Hence 3x^(2) + 2x - 4 = 0 Now apply the Quadratic Equation. x = { - 2 +/- sqrt[2^(2) - 4(3)(-4)]} / 2(3) x = {-2 +/- sqrt[4 + 48]} / 6 x = { -2 +/- sqrt(50_] / 6 x = { -2 +/-5sqrt(2)} / 6 x = (-2 - 5sqrt(2))/ 6 & x = (-2 + 5sqrt(2))/ 6 Since the square root of '2' is an Irrational Number. (decimals go to infinity, the answer is left in 'surd' form .
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
2x2 + 3x - 20 = (x + 4)(2x - 5).
2x2 + 10 = 9x 2x2 - 9x + 10 = 0 (x - 2)(2x - 5) = 0
2x2 + 10 - 9x = 0 or 2x2 - 9x + 10 = 0 So (x - 2)*(2x - 5) = 0
2x2 + 2x = 2x(x+1)
(2x + 1)(x + 3) = 0; x = -0.5 or -3
You would factor 2x2 + 7x + 6 into (2x + 3) (x+2)
4x4 + 1 = (2x2 - 2x + 1)(2x2 + 2x + 1)