x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
2x2 + 7x = 0 => x(2x+7)=0 so x = 0 or 2x+7 = 0 ie x = 0 or x = -7/2
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
x = -1.5 or -2 2x2 + 7x + 6 = 0 => (2x + 3)(x + 2) = 0 Thus 2x + 3 = 0 => x = -1.5 or x + 2 = 0 => x = -2
-7
x2 + 7x = 2x2 + 6 x2 - 2x2 + 7x = 6 -x2 +7x - 6 = 0 or alternatively x2 - 7x + 6 = 0
2x2-7x+3 = 0 (2x-1)(x-3) = 0 x = 1/2 or x = 3
2x2 + 7x = 0 => x(2x+7)=0 so x = 0 or 2x+7 = 0 ie x = 0 or x = -7/2
x2+7x=-2x2+6 3x2+7x-6=0 (3x-2)(x+3)=0 3x-2=0 or x+3=0 x=2/3 or x=-3
The answer is x=0
2x2 + 7x + 3 = (2x + 1)(x + 3)If 2x2 + 7x + 3 = 0 then:(2x + 1)(x + 3) = 0⇒ (2x + 1) = 0 → x = -1/2or (x + 3) = 0 → x = - 3
x = -1.5 or -2 2x2 + 7x + 6 = 0 => (2x + 3)(x + 2) = 0 Thus 2x + 3 = 0 => x = -1.5 or x + 2 = 0 => x = -2
2x2 + 7x - 15 = 02x2 + 10x - 3x - 15 = 0(2x2 - 3x) + (10x - 15) = 0x(2x - 3) + 5(2x - 3) = 0(2x - 3)(x + 5) = 0(2x - 3) = 0 or (x + 5) = 0x = 3/2 or x = -5
3
-7
63828
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0