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Such a polygon is not possible.

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Q: What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 14 feet?
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What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 2 feet?

10 square feet


Is a yield sign a regular polygon?

Yield signs are triangular, but have rounded corners. An actual triangular shape, if equilateral, would be a regular polygon.


Is the perimeter of a polygon less than the area of the polygon?

if your perimeter totals the same as 4 times pi then the maximum area that can be encompassed is equal to the perimeter. This is done by forming a circle. if you change the shape of the circle then the area will become smaller than the perimeter(circumference) if you make the circumference of the circle smaller then you will definitely decrease the area faster than you would the perimeter if you make the perimeter bigger then you will definitely increase the area faster than you would the perimeter.


What is the area of a regular hexagon with a side length of 4.5 m and an apothem length of 3.9 m?

Given the side length of a regular polygon you don't need the apothem and conversely. Using the side length, you get an area of 52.61 sq metres. Using the apothem, you get 52.69 sq metres. The difference between the two is because, if the side were exactly 4.5 m, then the apothem would be side*sqrt(3)/2. This is 3.897 m (to 3 dp) rather than 3.9. The difference leads to the answer for the area being 52.6 or 52.7 sq metres. However, the lengths are given to only 2 significant digits and to 2 sig digs, the area is 52 sq metres. This is a good example for people who insist on giving answers to spurious levels of accuracy.


What do you call a 58 sided shape?

Applying systematic polygon names, a 58-sided regular polygon would be called a pentacontakaioctagon.

Related questions

What would be the area of a regular polygon with a perimeter of 30 feet and an apothem of 4 feet?

60ft


What would be the area of a regular polygon with a perimeter of 30 feet and and apothem of 4 feet?

60ft


What would be the area of a regular polygon with a perimetr of 30ft and an apothem of 4ft?

The area of a regular polygon is equal to one-half the product of the apothem and the perimeter. 40x30 divided by 2=600 square feet


What would be the area of a regular polygon with a perimeter of 10 feet and an apothem of 2 feet?

10 square feet


What would be the area of a regular polygon with the perimeter of 10 feet and an apothem of 2 feet?

The answer will depend on the number of sides in the polygon. Since that information is not given, there can be no answer.


A regular octagon with sides of length 11 and an apothem of length 8.85 has an area of what?

An apothem of a regular polygon is a segment from its center to the midpoint of a side. You can use the apothem to find the area of a regular polygon using this formula: A = pa/2 where p is the perimeter of the figure and a is the apothem. For a regular octagon with side length 11, the perimeter p = 8(11) = 88. So the area would be A = 88(8.85)/2 = 389.4 square units.


What would be the area of a regular polygon with a perimeter of 10 feet and the apothem of 2 feet?

Area of regular polygon: 0.5*2*10 = 10 square feet


What would be the area of a regular polygon with the perimeter of 20 ft and apothem of 3 ft?

Area of regular polygon: 0.5*20*3 = 30 square feet


What would be the area of a regular polygon with a 20 feet and an apothem of 3 feet?

the formula for a regular polygon is A=1/2(apothem)(perimeter). So, first you would do 1/2 times 3 which equals 3/2. 3/2 times 20 is 30. so 30 is the area.


What would be the area of a polygon with a perimeter of 30 feet and a apothem of 4 feet?

60ft


What would be the area of a regular polygon with a perimeter of 20 feet and and apothem of 3 feet?

30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!


What would be the area of a regular polygon with a perimeter of 20 feet and an apothem of 3 feet?

30ft * * * * * No, it is 30 SQUARE feet. Area cannot be measured in feet!